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2 years ago

How many atoms in 8.2 moles of zinc

Chemistry

1 answer:

svetlana [45]2 years ago

7 0

Answer:

4.94x10^24 atoms Zn

Explanation:

By definition, there are 6.022x10^23 atoms in a mole of a substance. This is a conversion factor:

(6.022x10^23 atoms/mole)

(8.2 moles Zn)* (6.022x10^23 atoms/mole) = 4.94x10^24 atoms Zn

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Taya2010 [7]

Answer:

A. All of the other answers are correct

Explanation:

Each pairs are from the same elements, meaning they share the same atomic number but different nucleon number (neutron number + atomic number). Thus, all of the answers are correct.

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3 years ago

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3 years ago

What is the volume of 0.80 grams of O2 gas at stp?

sergey [27]

<u>Answer: </u>The volume occupied by $O_2$ at STP is 0.56 L.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of oxygen = 0.80 g

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Putting values in above equation, we get:

$\text{Moles of oxygen}=\frac{0.80g}{32g/mol}=0.025mol$

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Hence, the volume occupied by $O_2$ at STP is 0.56 L.

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4 years ago

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mrs_skeptik [129]

Answer:1. Energy 2. Medium 3. Original position 4. Waves 5. Matter

Explanation:

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3 years ago

A 1.268 g sample of a metal carbonate, MCO₃, was treated 100.00 mL of 0.1083 M H₂SO₄, yielding CO₂ gas and an aqueous solution o

attashe74 [19]

Answer:

MCO3 is BaCO3

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Explanation:

The first step in solving the question is to put down the balanced reaction equations as shown in the image attached. Secondly, we obtain the relative number of moles acid and base as mentioned in the question. The balanced neutralization reaction equation is used to obtain the number of moles of excess acid involved in the neutralization reaction.

This is then subtracted from the total number of moles acid to give the number of moles of acid that reacted with MCO3. From here, the molar mass of MCO3 and identity of M can be found. Hence the mass of CO2 produced is calculated as shown.

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3 years ago