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2 years ago

How many atoms in 8.2 moles of zinc

Chemistry

1 answer:

svetlana [45]2 years ago

7 0

Answer:

4.94x10^24 atoms Zn

Explanation:

By definition, there are 6.022x10^23 atoms in a mole of a substance. This is a conversion factor:

(6.022x10^23 atoms/mole)

(8.2 moles Zn)* (6.022x10^23 atoms/mole) = 4.94x10^24 atoms Zn

You might be interested in

A neutral atom of Cl-37 has

Ostrovityanka [42]

Answer:

17 protons, 20 neutrons, and 17 electrons.

Explanation:

A periodic table can be defined as the standard arrangement of chemical elements by atomic number, electronic configuration and chemical properties in a tabular form.

Generally, a proper representation of the mass number and atomic number of chemical elements is key and very important in chemistry.

Furthermore, as a rule, it should be noted that the mass number (nucleon number) is always larger than the atomic number(number of proton).

The mass number of this neutral atom of Cl-37 is 37 and we know that the atomic number (number of protons) of chlorine is 17. Also, the atomic number of an element is equal to the number of its electrons.

A neutral atom of Cl-37 has 17 protons, 20 neutrons, and 17 electrons.

Hence, a neutral atom of Cl-37 can be identified based on its number of protons because it represent its atomic number, which is what is used to differentiate an atom of an element from the atom of another chemical element.

6 0

3 years ago

a compound containing only carbon and hydrogen produces 1.80 gCO2 and 0.738 gH2O. Find the empirical formula of the compound. Ex

r-ruslan [8.4K]

Answer:

The empirical formula is CH2

Explanation:

Step 1: Data given

Mass of CO2 produced = 1.80 grams

Mass of H2O produced = 0.738 grams

Step 2: The balanced equation

CxHy + O2 → CO2 + H2O

Step 3: Calculate moles CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 1.80 grams / 44.01 g/mol

Moles CO2 = 0.0409 moles

Step 4: Calculate moles C

In 1 mol CO2 we have 1 mol CO2

In 0.0409 moles CO2 we have 0.0409 mol C

Step 5: Calculate moles H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 0.738 grams / 18.02 g/mol

Moles H2O = 0.04095 moles

Step 6: Calculate moles H

In 1 mol H2O we have 2 moles H

In 0.04095 moles H2O we have 2*0.04095 = 0.0819 moles H

Step 7: Calculate the mol ratio

We divide by the smallest amount of moles

C: 0.0409 / 0.0409 = 1

H: 0.0819 moles / 0.0409 = 2

The empirical formula is CH2

4 0

3 years ago

What mass of ch4 is consumed when 587. 9 kj of energy is evolved from the combustion of a mixture of ch4(g) and o2(g)? show the

katen-ka-za [31]

Mass of CH₄ is 10.591 g.

The molar mass is a crucial characteristic of the material that is independent of sample size. The coherent unit of molar mass in the International System of Units (SI) is kg/mol. However, molar masses are usually generally given in g/mol due to historical considerations.

A chemical compound's molar mass is calculated by dividing its mass by the number of moles of the substance that make up the sample.

Δg = 587.9 KJ

CH₄ Molar mass = 16.05 g/mol

mol CH₄ = Δg / ΔH°

= 587.9 / 890.3 KJ/ mol

= 0.6603 mol CH₄

Mass CH₄ = 0.6603 × 16.05 g/mol

= 10.591 g

Therefore, the mass of CH₄ is 10.591 g.

Learn more about molar mass here:

brainly.com/question/24236159

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8 0

1 year ago

Is A car traveling 33 km/h. accelerating

MArishka [77]

Answer:

where is the question?

Explanation:

5 0

3 years ago

A 645 g piece of iron is plunged into 375 g of water. The temperature of the water increases from 26 C to 87 C. If the heat capa

jeka94

Answer:

417 °C

Explanation:

From the question given above, the following data were obtained:

Mass of iron (Mᵢ) = 645 g

Specific heat capacity of iron (Cᵢ) = 0.449 J/gºC

Mass of water (Mᵥᵥ) = 375 g

Initial temperature of water (Tᵥᵥ) = 26 °C

Equilibrium temperature (Tₑ) = 87 °C

Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC

Initial temperature of iron (Tᵢ) =?

The initial temperature of iron can be obtained as follow:

Heat lost by iron = heat gain by water

MᵢCᵢ(Tᵢ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

645 × 0.449(Tᵢ – 87) = 375 × 4.184 (87 –26)

289.605(Tᵢ – 87) = 1569 × 61

289.605Tᵢ – 25195.635 = 95709

Collect like terms

289.605Tᵢ = 95709 + 25195.635

289.605Tᵢ = 120904.635

Divide both side by 289.605

Tᵢ = 120904.635 / 289.605

Tᵢ ≈ 417 °C

Thus, the original temperature of the iron is 417 °C

7 0

3 years ago