Answer:
Her Eid per Ruth Jααte Hαin wo Humse,
αb bαtαo Hum Eid Mαnαye yα unko.
ہر عید پر روٹھ جاتے ہیں وہ ہم سے
اب بتاؤ ہم عید منائے یا ان کو
ik ishq ka gam aafat aur us pe ye dil aafat
ya gam na diya hota ya dil na diya hota
bas ek jhijhak hai haal-e-dil sunaane mein,
ki tera bhi jikr aaega mere is phasaane mein.
kya kahoon kis tarah se jita hoon
gam ko khaata hoon aansoo pita hoon
Answer:
a) 6.3 cm
b) 8.0 cm
c) 0.7875
Explanation:
(a) The compound has moved above upto 7.3 cm from the bottom of the paper. Let us assume that line is drawn at 1.0 cm mark as the origin of spot. \
Distance traversed by compound= 7.3 - 1.0 cm = 6.3 cm
(b) Distance traversed by the solvent = 9.0 - 1.0 cm = 8.0 cm
(c) The Rf = Compound Migration distance / Solvent front migration distance
= 6.3/8.0 = 0.7875
A.
H20 and OH are a conjugate acid-base pair.
Answer:
<em>The grams of hydrogen gas that are released is 0.343 gram</em>
Explanation:
<em>Given that:</em>
<em>2 Na + 2h₂0 ⇒ 2Na0H +N₂</em>
<em>Molecules of Na = 7.9/2.3 = 0.343 mol Na</em>
<em>Now,</em>
<em>2 molecules of Na produces one mole h₂</em>
<em>0.343 mol of Na produce 0.343/2 = 0.1717 mol h₂</em>
<em>h2 = molecules * mw (molecular weight) =0.1717 * 2 =0.343 grams</em>
<em>Therefore the grams of hydrogen gas released is = 0.343 grams</em>
It's changes over time In the same person
