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seraphim [82]
2 years ago
10

R Given:07F = FRY: RFY: LFY

Mathematics
1 answer:
algol [13]2 years ago
8 0

S1: ∠YLF ≅ ∠FRY (Given)

S2: ∠RFY ≅ ∠LFY (Given)

S3: FY ≅ FY (Transitive property)

S4: ΔFRY ≅ ΔFLY (AAS theorem)

<h3>What is the AAS Congruence Theorem?</h3>

The AAS congruence theorem states that if two triangles have two pairs of corresponding congruent angles, and a pair of corresponding non-included side that are congruent, then both triangles area congruent.

To prove that ΔFRY ≅ ΔFLY, the proof that shows they are congruent by the AAS congruence theorem is:

S1: ∠YLF ≅ ∠FRY (Given)

S2: ∠RFY ≅ ∠LFY (Given)

S3: FY ≅ FY (Transitive property)

S4: ΔFRY ≅ ΔFLY (AAS theorem)

Learn more about the AAS Theorem on:

brainly.com/question/4460411

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The expression 35+45x represents a trains distance in miles from a terminal after X hours of travel
marin [14]

Answer:

35

Step-by-step explanation:

If it hasn't started X would be 0 so it be 35+45(0) that would give you 35.

6 0
3 years ago
3. Michel invests $850 at 7%/a simple interest. How long will he
Kipish [7]

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&\$200\\ P=\textit{original amount deposited}\dotfill & \$850\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ t=years \end{cases} \\\\\\ 200=850(0.07)t\implies \cfrac{200}{850(0.07)}=t\implies \stackrel{\textit{about 3 years, 4 months and 10 days}}{3.36\approx t}

5 0
2 years ago
One person wants to get a 95% z-confidence interval with a margin of error of at most 15 based on a population standard deviatio
Bess [88]

Answer:

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=60 represent the population standard deviation  

n represent the sample size (variable of interest)  

Confidence =95% or 0.95

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =15, and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

6 0
4 years ago
Stevens friends are buying tickets to a concert. Each person pays $8. How much money do they pay altogether
ololo11 [35]
Un answerable how many friends buy tickets?
4 0
4 years ago
Will give brainliest, Use properties of exponents to write an equivalent expression.
Sav [38]

Answer:

see attached

Step-by-step explanation:

4 0
3 years ago
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