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dexar [7]
2 years ago
6

Which value for x completes the conditional relative frequency table by column? 0. 17 0. 25 0. 40 0. 85.

Mathematics
1 answer:
matrenka [14]2 years ago
4 0

A relative frequency table is a graph that depicts the popularity or pattern of a certain piece of data based on the population sampled. The value of x will be 85.

<h3>What is a relative frequency table?</h3>

A relative frequency table is a graph that depicts the popularity or pattern of a certain piece of data based on the population sampled.

When we examine the relative frequency, we examine the number of times a certain event happens in comparison to the overall number of events.

We have the following equation for the adult column;

\rm  x + 0.15 = 1

\rm  x = 1-0.15\\\\\rm  x = 0.85

Hence the value of x will be 85.

To learn more about the relative frequency table refer to the link;

brainly.com/question/1809498

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Mr. Wonka optimized your team’s box to maximize chocolate bar sales. The new volume is (x^3-9x) inches ^3, the length is (x+3) a
lyudmila [28]

Answer:

x^2-3x

Step-by-step explanation:

If we use polynomial division

          x^2-3x

x+3 | x^3+0x^{2} -9x

         <u> </u>x^3+3x^2<u>               </u>

                -3x^2-9x

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8 0
3 years ago
1/2x -2 =8 solve for x<br>​
ser-zykov [4K]

Answer:

x=4

Step-by-step explanation:

1/2x -2= 8

add 2 to both sides

1/2x = 10

multiply 1/2 to both sizes

x= 8/2 o

multiply

x= 4

3 0
3 years ago
The tables show the number of chin-ups done by students in two different gym classes. 2nd Period 3 4 12 14 7 7 8 4 8 3 11 10 9 8
Mekhanik [1.2K]

Answer:

On average, students in the 4th period did more chin-ups than students in the 2nd period

Step-by-step explanation:

Given the table values as

2nd Period     3  4 12 14 7  7  8  4  8  3  11  10  9   8 10 4  8 7  13 9

4th Period      10 3 14 14 16 15 7 12 7  10 12  8  10  9 6  11  9 1   2 5

Find the average chin-ups done by students in the gym classes

For 2nd Period gym class, the average will be;

=sum of chin-ups ÷ number of students

=sum of chin-ups in 2nd period gym class=

=3 + 4 +12+ 14+ 7 + 7 + 8+  4 + 8 + 3+  11+  10+  9 +  8 +10+ 4+  8+ 7 + 13+ 9\\\\=159

=number of students=20

Average=159÷20

=\frac{159}{20} =7.95\\\\\\=8

For 4th Period gym class

Sum of chin-ups=

=10+ 3+ 14+ 14 +16 +15+ 7 +12 +7+ 10+ 12 +8+ 10+ 9+ 6+ 11+ 9 +1 +2 +5\\\\\\=181

Number of students=20

Average number of chin-ups in the 4th period gym class

=\frac{181}{20} =9.05\\\\\\=9

Average number of chin-ups in 2nd Period Class = 8

Average number of chin-ups in 4th Period Class= 9

Conclusion; On average students in the 4th period gym class made more chin-ups (9) than those in 2nd period gym class (8).

3 0
4 years ago
Read 2 more answers
Here you go it is here now
Valentin [98]

Answer:

40+10=50

40+-15=25

40+-30=10

40+-40=0

40+-50=-10

20+-25=-5

Step-by-step explanation:

in this order

3 0
3 years ago
Read 2 more answers
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