Answer:
Step-by-step explanation:
Option A is the correct answer
Because the further process is correct
<h2><u>Solution</u> :-</h2>
Given : Radius of cylinder = 8 m
Height = 4 m
Volume of cylinder = πr²h cu. units
= 22/7 × 8 × 8 × 4 m³
= 804.57 m³ (approx.)
Curved surface area = 2πrh sq. units
= 2 × 22/7 × 8 × 4 m²
= 201.14 m² (approx.)
Total surface area = 2πr(r + h) sq. units
= 2 × 22/7 × 8 (8 + 4) m²
= 2 × 22/7 × 8 × 12 m²
= 603.43 (approx.)
2[4 − 7(3x + 4y)] + 2[3x(−2y)]
2[4 - 21x -28y] + 2[-6xy]
8 - 42x - 56y -12xy
the perimeter of given rectangular garden is (8 - 42x - 56y -12xy).
Answer:
it should be 3.) x+2
Step-by-step explanation:
Answer:
11, 60.61
Step-by-step explanation:
this is the only set that fits a^2 +b^2=c^2
you square the first two numbers, add them together. Then you take the square root of that sum. This number must equal the third number for it to be a triple.
