What is the sector area created by the hands of a clock with a radius of 9 inches when the time is 4:00?
2 answers:
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Answer:
(5, 8), (7, 1), (15, 3)
Step-by-step explanation:
a) The variables are defined in the problem statement. The total expenditure must satisfy ...
2.00x +3.50y ≤ 42.00
b) Possible solutions include ...
(x, y) ∈ {(5, 8), (7, 1), (15, 3)}
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These were chosen by looking at the attached graph of the equation.
Answer:
3a) The value of x = 56
3b) The measure of ∠ H T M = 90°
3c) The radius of the circle = 53
Step-by-step explanation:
3a) ∵ A F is a tangent to the circle O at point F
∵ Secant AH intersects circle O at point T
∴ (A F)² = (A T)(A H)
∴ 7( x + 7) = (21)² ⇒ ÷ 7
∴ x + 7 = 63
∴ x = 63 - 7 = 56
3b) ∵ HM is a diameter
∴ The measure of the arc HM = 180° ⇒ semi-circle
∵ ∠ H T M is inscribed angle subtended by the arc HM
∴ m ∠ H T M = half the measure of arc HM
∴ m ∠ H T M = 180° ÷ 2 = 90°
3c) ∵ Δ H T M is a right angle triangle at T
∴ (H M)² = (M T)² + (H T)² ⇒ Pythagorean theorem
∴ (H M)² = (90)² + (56)²
∴ (H M)² = 11236
∴ HM = = 106
∴ OM = 106 ÷ 2 = 53
∵ OM is the radius of the circle O
∴ The radius = 53