Q10 Q2.) Find the standard form of the equation of the parabola satisfying the given conditions.

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

3 0

To solve this problem you must apply the proccedure shown below:

1. You have that the standard form of the equation of the parabola must satisfy the following conditions given in the exercise above:

Focus: (-1,4) and Directrix: y=2

2. Therefore you have:

√(x0-(-1))²+(y0-4)²=|y0-2|
(x0+1)²+(y0-4)²=(y0-2)²

3. When you simplify the expression above and clear y0, you obtain:

y0=y

y=1/4(x²+2x+13)
y=(x²/4)+(x/2)+(13/4)

Therefore, the answer is: y=(x²/4)+(x/2)+(13/4)

You might be interested in

What is -(5x+6)-x=-6-6x

Veronika [31]

Answer: All real numbers are solutions.

Step-by-step explanation:

Let's solve your equation step-by-step.

−(5x+6)−x=−6−6x

Step 1: Simplify both sides of the equation.

−(5x+6)−x=−6−6x

−5x+−6+−x=−6+−6x(Distribute)

(−5x+−x)+(−6)=−6x−6(Combine Like Terms)

−6x+−6=−6x−6

−6x−6=−6x−6

Step 2: Add 6x to both sides.

−6x−6+6x=−6x−6+6x

−6=−6

Step 3: Add 6 to both sides.

−6+6=−6+6

0=0

8 0

3 years ago

Find the probability that in a pig family of 4 offspring there will be at least 1 male and 1 female. Assume that the probability

Naya [18.7K]

The probability of there being zero males is given by:
$P(zero\ males)=4C0\times0.5^{0}\times0.5^{4}=\frac{1}{16}$
Similarly the probability of there being zero females is also 1/16.
The probability there will be at least 1 male and 1 female is therefore:
$1-(\frac{1}{16}+\frac{1}{16})=\frac{7}{8}$
The answer is: 7/8.

5 0

3 years ago

Ayuda por favor/Help please

Akimi4 [234]

X=2

El mejor programa para que te ayuda es Math,

way

4 0

2 years ago

During a musical, an orchestra is playing. As the music plays, the volume changes at the beginning of the piece can be modeled b

Ivanshal [37]

Answer: