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tino4ka555 [31]
3 years ago
12

Q10 Q2.) Find the standard form of the equation of the parabola satisfying the given conditions.

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
3 0
To  solve this problem you must apply the proccedure shown below:

 1. You have that the standard form of the equation of the parabola must satisfy the following conditions given in the exercise above:

 Focus: (-1,4) and Directrix: y=2

 2. Therefore you have:

 √(x0-(-1))²+(y0-4)²=|y0-2|
 (x0+1)²+(y0-4)²=(y0-2)²

 3. When you simplify the expression above and clear y0, you obtain:

 y0=y

 y=1/4(x²+2x+13)
 y=(x²/4)+(x/2)+(13/4)

 Therefore, the answer is: y=(x²/4)+(x/2)+(13/4)
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Last year, the volleyball team paid $5 pair for socks and $17 per pair for shorts on a total purchase of $315. This year they sp
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Option E is correct.

12 pairs of socks and 15 pairs of shorts did team buy each year.

Step-by-step explanation:

Let the number of pairs of socks be x and the number pairs of shorts be y.

As per the statement:

Last year, the volleyball team paid $5 pair for socks and $17 per pair for shorts on a total purchase of $315.

⇒5x+17y = 315                   .....[1]

It is also given that: This year they spent $342 to buy the same number of socks and shorts, because the socks now cost $6 a pair and the shorts cost $18.

⇒6x + 18y = 342                   .....[2]

Multiply equation [1] by 6 both sides we get;

30x+102y = 1890                 .......[3]

Multiply equation [2] by 5 both sides we get;

30x +90y = 1710                   .....[4]

Subtract equation [4] from [3] we get;

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Divide both sides by 168 we get;

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Subtract 255 from both sides we get;

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Divide both sides by 5 we get;

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Therefore, 12 pairs of socks and 15 pairs of shorts did team buy each year.

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