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3 years ago

Please solve the given problem please please please please please please please please

Mathematics

1 answer:

Serjik [45]3 years ago

7 0

(9x 3) x (8 divied 5)

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3 years ago

PLS HELP NOW I DONT UNDERSTAND

Leona [35]

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3 years ago

What is the value of x?

Kamila [148]

Given the fact that 95 is on the right side of the line
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8 0

4 years ago

Read 2 more answers

What must be the sides of an equilateral triangle so that it's area should be equal to the area of an isosceles triangle with ba

d1i1m1o1n [39]

Answer:

The sides of the equilateral triangle are 11.7 m.

Step-by-step explanation:

Let's find the area of the isosceles triangle:

$A_{i} = \frac{bh}{2}$

Where:

b: is the base = 12 m

h: is the height

We can find the height by using Pitagoras:

$x^{2} = \frac{b^{2}}{2} + h^{2}$

Where:

x is the hypotenuse = side of the triangle = 10 m

$h = \sqrt{x^{2} - \frac{b^{2}}{2}} = \sqrt{(10)^{2} - 6^{2}} = 8 m$

Then, the area is:

$A_{i} = \frac{12*8}{2} = 48 m^{2}$

Now, since the area of the isosceles triangle is equal to the area of the equilateral triangle:

$A_{e} = A_{i} = 48 m^{2}$

$A_{e} = \frac{bh}{2}$

The height of the equilateral triangle is given by:

$b^{2} = \frac{b^{2}}{2} + h^{2}$

$h = \sqrt{b^{2} - \frac{b^{2}}{2}} = \frac{b}{\sqrt{2}}$

Hence, the sides are:

$A_{e} = \frac{1}{2}b\frac{b}{\sqrt{2}} = \frac{b^{2}}{2\sqrt{2}}$

$b = \sqrt{A*2\sqrt{2}} = \sqrt{48*2\sqrt{2}} = 11.7 m$

Therefore, the sides of the equilateral triangle are 11.7 m.

I hope it helps you!

7 0

3 years ago

Read 2 more answers

Please solve the given problem please please please please please please please please​

Please solve the given problem please please please please please please please please