(1) The number of moles of oxygen gas is 0.123 mole.
(2) The volume occupied by the nitrogen gas is 50.75 Liters.
(3) The pressure exerted by the CO2 gas is 28.7 atm
(4) The temperature of the Cl2 gas is -118.37⁰C
<h3>
Number of moles of oxygen</h3>
The number of moles of oxygen occupied at the given condition is calculated as follows;
PV = nRT
n = PV/RT
where;
- T = 25ºC = 273 + 25 = 298K
- R is ideal gas constant = 0.08205 L.atm/mol.K
n = (2.5 x 1.2) / (0.08205 x 298)
n = 0.123 mol
<h3>Volume of the gas</h3>
PV = nRT
V = nRT/P
where;
V = (2 x 62.36 x 293) / (720)
V = 50.75 Liters
<h3>Pressure of the gas</h3>
PV = nRT
P = nRT/V
where;
Molar mass of CO2 = 44
n = 25/44 = 0.568
P = (0.568 x 0.08205 x 308)/(0.5)
P = 28.7 atm
<h3>Temperature of the gas</h3>
T = PV/nR
molar mass of Cl2 = 71 g
n = 5/71 = 0.07
T = (900 x 0.75)/(0.07 x 62.36)
T = 154.63 K
T = 154.63 - 273 = -118.37⁰C
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