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Ymorist [56]
3 years ago
14

I need help with this pls help !!

Chemistry
1 answer:
Doss [256]3 years ago
4 0

Answer:

70g of HCl

Check the attachment below. Locate 25C and then follow the line where it meets the curve.

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Answer:

FeSO2

Explanation:

Please see attached picture for full solution.

8 0
3 years ago
Which statement explains the relationship between the amount of energy it takes to break a bond and the amount of energy release
ad-work [718]

<em>The statement that gives the relationship between energy needed in breaking a bond and the one that is released after breakin</em>g is

The amount of energy it takes to break a bond is always less than the amount of energy released when the bond is formed.

  • Bond energy can be regarded as amount of energy that is required in  breaking a particular bond.

  • For a bond to be broken Energy will be  added and when a bond is broken there will be release of energy

  • Bond breaking can be regarded as endothermic process, it is regarded as endothermic  because there is a lot of energy required to be absorbed.

  • Where ever a bond is broken, there must be formation of another bond

  • Bond forming on the other hand can be regarded as exothermic process, since there is a release of  releases energy.

Therefore, more energy is required in breaking of bond compare to energy released after breaking of bond.

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6 0
3 years ago
PLEASE HELP!! GIVING BRAINLIEST
RSB [31]

Answer:

The answer is "0.00172172603".

Explanation:

Given:

Mass (M) = 1.60 \times  10^{-3} \ g\\\\Density (D) = 9.293 \times 10^{-1} \ \frac{g}{cm^3}\\\\Volume (V) =  ?

Formula:

\to \bold{V = \frac{M}{D}}

       = \frac{1.60 \times  10^{-3}}{9.293 \times  10^{-1}} \\\\  = \frac{1.60 \times  10^{1}}{9.293 \times  10^{3}} \\\\ = \frac{1.60 \times  10}{9.293 \times  1000} \\\\ = \frac{1.60 }{9.293 \times  100} \\\\ = \frac{1.60 }{929.3 } \\\\= 0.00172172603

4 0
3 years ago
Which of the following factors affects the strength of the gravitational force between two objects?
mash [69]
D. the distance between the objects
6 0
3 years ago
Read 2 more answers
How many grams of NaOH needed to completely neutralize 3L of 1.75M HCL
Sedaia [141]

Answer:

209.98 g of NaOH

Explanation:

We are given;

  • Volume of HCl as 3 L
  • Molarity of HCl as 1.75 M

We are required to calculate the mass of NaOH required to completely neutralize the acid given.

First, we write a  balanced equation for the reaction between NaOH and HCl

That is;

NaOH + HCl → NaCl + H₂O

Second, we determine the number of moles of HCl

Number of moles = Molarity × Volume

                             = 1.75 M × 3 L

                             = 5.25 moles

Third, we use the mole ratio to determine the moles of NaOH

From the reaction,

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = Moles of HCl

                          = 5.25 moles

Fourth, we determine the mass of NaOH

Molar mass of NaOH = 39.997 g/mol

Mass of NaOH = 5.25 moles × 39.997 g/mol

                        = 209.98 g

Thus, 209.98 g of NaOH will completely neutralize 3L of 1.74 M HCl

6 0
3 years ago
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