Question

A regular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm. what is the approximate area of the heptagon rounded to the nearest whole number? recall that a heptagon is a polygon with 7 sides. 1,173 cm2 2,125 cm2 2,359 cm2 4,250 cm2

Answer 1

The area of the regular heptagon which has a radius of approximately 27.87 cm and the length of each side is 24.18 cm is 2125 cm².

What is the area of a heptagon?

Heptagon is the closed shape polygon which has 7 sides and 7 interior angles.

The area of the regular heptagon is found out using the following formula.

$A=\dfrac{7a}{4}\cot \left(\dfrac{180}{7}\right)$

Here, (a) is the length of the heptagon.

A regular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm. Put the value of side in the above formula,

$A=\dfrac{7\times24.18}{4}\cot \left(\dfrac{180}{7}\right)\\A\approx 2125\rm\; cm^2$

Hence, the area of the regular heptagon which has a radius of approximately 27.87 cm and the length of each side is 24.18 cm is 2125 cm².

Learn more about the area of a heptagon here;

brainly.com/question/26271153