Answer:
8,000 - 24x
Step-by-step explanation:
Let
y ----> depreciated value of the car
x---> rate of depreciation
t ----> the time in months
we know that
The linear equation that represent this situation is
y=8,000-xt
For t=2 years=2*12=24 months
substitute
y=8,,000-x(24)
y=8,000-24x
Try multiplying it
we know that 8 times 10=80 so multiply 80 by 2, then 3 then 4 untill you get close to that number so
80 times 2=160
80 times 3=240
80 times 4=320
this is over so it is more than 30 8's but less than 40 8's
so start from 320
subtract 293 from 320
320-293=27
divide 27 by 8
27/8=3 and 3/8
add that to 30
33 and 3/8 8's will fit
the teacher probably wants how many whole 8's can fit so get rid of the 3/8 and just put 33 8's
Answer:
8r+16r=24r
Step-by-step explanation:
Answer:
-28,000
and also that goat is soooo cute
Answer:
sinA = ± 
Step-by-step explanation:
Using the Pythagorean identity
sin²A + cos²A = 1 ( subtract cos²A from both sides )
sin²A = 1 - cos²A ( take the square root of both sides )
sinA = ±
