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3 years ago

Please please help I don’t understand this

Computers and Technology

2 answers:

garik1379 [7]3 years ago

6 0

Answer:

It is this because yass

Explanation:

And yes

Margarita [4]3 years ago

6 0

Answer:

Yes it is this because yes

Explanation:it is this because

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The vertical and horizontal scroll bars can be used to aid in navigation throughout the document. true or false

Triss [41]

Answer: True

Hope this helps :)

7 0

3 years ago

Read 2 more answers

Suppose a host has a 1-MB file that is to be sent to another host. The file takes 1 second of CPU time to compress 50%, or 2 sec

kozerog [31]

Answer: bandwidth = 0.10 MB/s

Explanation:

Given

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.50 MB / Bandwidth)

Transfer Size = 0.50 MB

Total Time = Compression Time + RTT + (0.50 MB /Bandwidth)

Total Time = 1 s + RTT + (0.50 MB / Bandwidth)

Compression Time = 1 sec

Situation B:

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.40 MB / Bandwidth)

Transfer Size = 0.40 MB

Total Time = Compression Time + RTT + (0.40 MB /Bandwidth)

Total Time = 2 s + RTT + (0.40 MB / Bandwidth)

Compression Time = 2 sec

Setting the total times equal:

1 s + RTT + (0.50 MB / Bandwidth) = 2 s + RTT + (0.40 MB /Bandwidth)

As the equation is simplified, the RTT term drops out(which will be discussed later):

1 s + (0.50 MB / Bandwidth) = 2 s + (0.40 MB /Bandwidth)

Like terms are collected:

(0.50 MB / Bandwidth) - (0.40 MB / Bandwidth) = 2 s - 1s

0.10 MB / Bandwidth = 1 s

Algebra is applied:

0.10 MB / 1 s = Bandwidth

Simplify:

0.10 MB/s = Bandwidth

The bandwidth, at which the two total times are equivalent, is 0.10 MB/s, or 800 kbps.

(2) . Assume the RTT for the network connection is 200 ms.

For situtation 1:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 1 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.50 MB

Total Time = 1.2 sec + 5 sec

Total Time = 6.2 sec

For situation 2:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 2 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.40 MB

Total Time = 2.2 sec + 4 sec

Total Time = 6.2 sec

Thus, latency is not a factor.

5 0

3 years ago

Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional

kumpel [21]

Explanation:

hope this help here is the answer

3 0

4 years ago

. Write a function definition as follows: it returns the C++ form of a Boolean value, its function identifier is anyTwoTheSame,

Paraphin [41]

Answer:

The c++ code to implement the Boolean function is given. The function definition is shown.

bool anyTwoTheSame(float a, float b, float c)

{

bool same = false;

if(a == b)

same = true;

else if(a == c)

same = true;

else if(b == c)

same = true;

return same;

}

Explanation:

This function accepts three floating point numbers and returns true if any two numbers are equal else returns false.

The program below shows the implementation of this method.

#include <iostream>

using namespace std;

bool anyTwoTheSame(float a, float b, float c);

bool anyTwoTheSame(float a, float b, float c)

{

bool same = false;

if(a == b)

same = true;

else if(a == c)

same = true;

else if(b == c)

same = true;

return same;

}

int main() {

float one=12.34, two=56.78, three=90.1;

cout<<"Two numbers are same : " <<anyTwoTheSame(one, two, three);

}

OUTPUT

Two numbers are same : 0

The method is first declared.

bool anyTwoTheSame(float a, float b, float c);

Next step is method definition which shows what the function is supposed to do. The test to check equality of two numbers is implemented as shown.

bool same = false;

if(a == b)

same = true;

else if(a == c)

same = true;

else if(b == c)

same = true;

This is the simplest test which can be programmed.

If the numbers are not same, the Boolean variable, same, remains initialized to false.

This function is then called in main method.

No user input is taken as this is not specified in the question.

The three floating variables are declared and initialized inside the main. The values are put inside the program and not taken from the user.

The output shows either 0 or 1. 0 represents false and 1 represents true.

This program can be tested for different values of floating variables.

3 0

3 years ago

Which of the following people was a member of FFA?

strojnjashka [21]

Answer: Tim McGraw

Explanation:

The National FFA Organization is a youth organization that originally aimed to encourage the youth to venture into agriculture by offering agriculture education to youth in high schools and middle schools. In recent years they started offering education in other areas such as business and technology.

The FFA is quite famous and has had and still has a lot of members. It is of no surprise therefore that some of their alumni are now stars. Famous Country musician Tim McGraw is one such alumni and he was a member of the FFA in his hometown of Start, Louisiana.

Other stars who were part of the FFA include; Taylor Swift and Sterling Martin.

8 0

4 years ago