Answer and Explanation:
In C programming language:
char fun(int*a, int*b){
printf("enter two integers: ");
scanf("%d%d",a,b);
int e;
printf("please enter a character: ");
e=getchar();
return e;
}
int main(int argc, char *argv[]) {
int d;
int f;
int g;
fun();
printf("%d%d%d", d, f, g);
}
We have declared a function fun type char above and called it in main. Note how he use the getchar function in c which reads the next available character(after the user inputs with printf()) and returns it as an integer. We then return the variable e holding the integer value as char fun() return value.
Explanation:
<h2>
<em><u>Edge computing with 5G creates tremendous opportunities in every industry. It brings computation and data storage closer to where data is generated, enabling better data control, reduced costs, faster insights and actions, and continuous operations. In fact, by 2025, 75% of enterprise data will be processed at the edge, compared to only 10% today.¹</u></em></h2><h2 /><h2>
<em><u>Edge computing with 5G creates tremendous opportunities in every industry. It brings computation and data storage closer to where data is generated, enabling better data control, reduced costs, faster insights and actions, and continuous operations. In fact, by 2025, 75% of enterprise data will be processed at the edge, compared to only 10% today.¹IBM provides an autonomous management offering that addresses the scale, variability and rate of change in edge environments. IBM also offers solutions to help communications companies modernize their networks and deliver new services at the edge.</u></em></h2>
Hope this answer is helpful
Answer:I call it life
Explanation:Without it I’m dead
When numbers are divided, the integer portion is kept and the remainder is disregarded (meaning 10/9 would return 1). Following this format, we get the answer of <span>6 6 6 3 7 7 9 5 8 8.
I also see that this program can be optimized because you use the same for loop twice, and both of them manipulate list elements in some way. A more optimized program would be:
</span><span>int a [] = {64 , 66 , 67 , 37 , 73 , 70 , 95 , 52 , 81 , 82};
for (int i = 0; i < a.length; i++) {
a[i] = a[i] / 10;
</span>System.out.print(a[i] + " ");<span>
}
Or maybe you don't need to store the list values for later on. You could do:
</span>for (int i = 0; i < a.length; i++) {
System.out.print(a[i] / 10 + " ");
}
In any situation, your answer is choice 2.
