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PolarNik [594]
2 years ago
11

Two soup cans p and q are right circular cylinders. each can has the same height, 5 inches, but the radius of can p is 2 inches,

and the radius of can q is 4 inches. how many times larger is the volume of can q than the volume of can p?
Mathematics
1 answer:
ASHA 777 [7]2 years ago
5 0

Answer: B. 4

Sorry for the really late answer

Step-by-step explanation:

If the radius of a right circular cylinder is multiplied by k, and its height does not change, then the volume of the cylinder is multiplied by k². The radius of can Q is twice as great as the radius of can p. Therefor, the volume of can Q is 2², or 4 times larger than the volume of can p.

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F(x) =- (3x +9) – 13 find f(-5)
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How do you solve 34.86 x 1.2?
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Answer: 41.832

Step-by-step explanation:

I like to write decimals without decimals when multiplying. for this I would do  

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The lateral area of a cylinder is 325 pi inch^2. The radius is 13 in. Find the surface area and volume. Please show all work!!!
USPshnik [31]
Answer:

Surface area =  663π in².
Volume = (676/3)π in² ≈ 225.33 π in²

Explanation:


1) We know the radius and the lateral area.

2) With the radius you can find the areas of the top and the bottom.

For that, you use the formula: 

area of the top = area of the bottom = π r² 


∴ π (13 in)² = 169π in² (each)


3) Then, the surface area is the sum of the lateral area and the two bases (top and bottom)

surface area = lateral area + bottom area + top area = 325π in² + 2×169π in² = 663π in².

3) You  can also find the height of the cylinder.

Use the formula: lateral area = 2π r h


∴ h = lateral area / [2 π r]

⇒ h = 325 π / [ 2π (13) ] = 12.5 in


4) With  the height you can find the volume.

Use the formula: V = (4/3) π r³ 

∴ V = (4/3) π (13 in)³ = (676/3)π in² ≈ 225.33 π in²
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3 years ago
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3 years ago
Read 2 more answers
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