The foci of the hyperbola with equation 5y^2-4x^2=20 will be given as follows:
divide each term by 20
(5y^2)/20-(4x^2)/20=20/20
simplifying gives us:
y^2/4-x^2/5=1
This follows the standard form of the hyperbola
(y-k)²/a²-(x-h)²/b²=1
thus
a=2, b=√5 , k=0, h=0
Next we find c, the distance from the center to a focus.
√(a²+b²)
=√(2²+(√5)²)
=√(4+5)
=√9
=3
the focus of the hyperbola is found using formula:
(h.h+k)
substituting our values we get:
(0,3)
The second focus of the hyperbola can be found by subtracting c from k
(h,k-c)
substituting our values we obtain:
(0,-3)
Thus we have two foci
(0,3) and (0,-3)
Answer:
<h2>The answer is b⁴</h2>
Step-by-step explanation:
Using the rules of indices
That's
Since the bases are the same and are dividing we subtract the exponents
So we have
We have the final answer as
<h2>b⁴</h2>
Hope this helps you
Multiply -7 to both sides:
Add 10 to both sides:
Divide 2 to both sides:
For this case we have the following line:
x = 4
The first thing you should know is that the slope of the line is given by:
m = (y2-y1) / (x2-x1)
In this case:
x2 = x1
Thus,
The slope is:
m = (y2-y1) / (0)
m = infinity
Answer:
The slope of the line is:
m = infinity
