2(10)+ 2(x-4) i dont get it

Mathematics

2 answers:

hoa [83]3 years ago

7 0

Answer:

2x + 12

Step-by-step explanation:

kondaur [170]3 years ago

3 0

Answer:

18x

Step-by-step explanation:

2(10) + 2(x-4)

first you would multiply 2 x 10 = 20

now we have the equation

20+2(x-4)

we now add 20 and 2

so now we have

22(x-4)

22-4= 18x

so the answer is <em>18x</em>

You might be interested in

Solve for t. 3t 35=6

zhenek [66]

The answers 9. I took the test :)

3 0

3 years ago

A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result: