7(a^2+b)-4(a^2+b)
7(a^2)+7b-4(a^2)-4b
7a^2-4a^2+7b-4b
(7-4)a^2+(7-4)b
3a^2+3b
Answer:
Look at attachment!
Step-by-step explanation:
E2020 Said so!
Answer:
a) There is an integer a such that is an integer
b) False
Step-by-step explanation:
Statement : ∀a ∈ Z, (a − 1) a is not an integer
A) The correct negation will be :
There is an integer a such that is an integer
B) The Given statement is FALSE because
when we assume the value of a = 1
( a - 1 ) / a = (1 - 1 ) / 1 = 0 ; which is an integer
Answer:
A( multiply both sides by 6)
As seen , the L.C.M is 6 so to do away with the fractional form, we will multiply by 6
Your answer would be y=3 1/2 ,y=3.5