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Serggg [28]
3 years ago
13

Express this number in standard form. 2.456×10^​11

Mathematics
2 answers:
rosijanka [135]3 years ago
8 0
Move the decimal to the right 11 times. 2,456,00,000,000
Marat540 [252]3 years ago
7 0

Answer:

2.456\times 10^{11}=245600000000

Step-by-step explanation:

Given : Number 2.456\times 10^{11}

To find : Express this number in standard form ?

Solution :

Standard from is writing number into larger form.

Expanding the given number 2.456\times 10^{11}

2.456\times 10^{11}=\frac{2456}{1000}\times 100000000000

2.456\times 10^{11}=2456\times 100000000

2.456\times 10^{11}=245600000000

Therefore, The standard form of the number 2.456\times 10^{11}=245600000000

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The rain fell at 2cm per hour

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Which number is greater:<br> -20 or -24
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-20

Step-by-step explanation:

-20 is greater. Since both numbers are negative, the closest number to zero is technically greater.

4 0
3 years ago
A crew is made up of 8 men; the rest are women. If 32 % of the crew are men, how many people are in the crew?
Lelechka [254]

Answer:

12

Step-by-step explanation:

(66 2/3)

---------- (x) = 8

  100

Solve for x

(66 2/3)x = 800

x = 800/(66 2/3)

x = 800/(200/3)

x = 800(3/200)

x = 4(3)

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8 0
3 years ago
What is the percent increase between 1200 grams and 550 grams
makkiz [27]

Answer:118%


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7 0
3 years ago
A flea jumps from the ground to a height of 30 cm and travels 15 cm horizontally from where it started. Suppose the origin is lo
adelina 88 [10]

Answer:

y=-\frac{8}{15}x^2+8x

Step-by-step explanation:

Consider the equation that shows flea's motion is y=ax^2+bx+c.

Since the origin is located at the point from where the flea jumped,

So, y=ax^2+bx+c  passes through (0,0).

That is, (0,0) must satisfy y=ax^2+bx+c,

0=a(0)^2+b(0)+c

\implies c =0

Now, it travels 15 cm horizontally from where it started.

That is, y=ax^2+bx+c  passes through (15,0).

0=a(15)^2+b(15)+c

0=a(225)+b(15)   (Because c=0)

225a+15b=0  ...... (1)

Again, it jumps from the ground to a height of 30 cm,

So, the y-coordinate of vertex of y=ax^2+bx+c is 30.

Now, the x-coordinate of vertex of the quadratic function must be half of the distance from its starting point to final point.

That is, x-coordinate of the vertex = \frac{15}{2} = 7.5,

Thus, vertex = (7.5, 30)

(7.5, 30) must satisfy y=ax^2+bx+c

That is, 30=a(7.5)^2+b(7.5)+c

30=56.25a+7.5b

56.25a+7.5b=30                ...... (2)

Equation (1) - 2 × equation (2),

225a - 112.5a = -60

112.5a = -60

\implies a = -\frac{60}{112.5}=-\frac{8}{15}

From equation (1),

225(-\frac{8}{15})+15b = 0

-120+15b=0

15b=120

b=8

Substitute the values of a, b and c in the quadratic equation y=ax^2+bx+c,

y=-\frac{8}{15}x^2+8x

Which is the required quadratic equation.

6 0
3 years ago
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