All categories

2 years ago

FIND THE EXACT AREA PLEASE HELPPPP ILL GIVE BRAINLIESTTTT

Mathematics

1 answer:

Ede4ka [16]2 years ago

4 0

Answer:

555.94

Step-by-step explanation:

16 x 11 = 176/2

since there are two of the same triangle

88 x 2

176

11 is the radius

A = $\pi$ $x^{2}$

A = 3.14 ( pie is 3.14, if not then pi) x (11x11)

A = 3.14 x 121 (or 121 $\pi$ )

A = 379.94

379.94 + 176 (or 121pi + 176)

555.94

You might be interested in

A proportional relationship between the number of pounds of potatoes (x) and the price in dollars (y) is graphed, and the ordere

olga55 [171]

Answer:

Part A: The price of 1 pound of potatoes is 1 dollar and 25 cents (1.25) because 5 / 4 is 1.25 and that's 1 pound

Part B: The ordered pair (10, 8) represents that 10 punds of potatoes cost 8 dollars

4 0

2 years ago

Is the given number a solution of the equation? 8=2+3; 10

kykrilka [37]

Answer:

No.

Step-by-step explanation:

8 doesn't equal 0 on the very right, which means it's not a solution to the equation. So therefore, it is false based on the equation.

7 0

3 years ago

Which one? I can’t figure it put

Romashka [77]

Answer:corresponding angles

I am very sure

Step-by-step explanation:

8 0

3 years ago

The fourth-grade students at Harvest School make up 0.3 of all students at the school. Witch fraction is equivalent to 0.3? -Zya

Leni [432]

3/10 or three tenths

4 0

3 years ago

Read 2 more answers

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago