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RUDIKE [14]
2 years ago
14

Let's say you want to know how many pages your 10 favorite books have. After checking

Mathematics
1 answer:
oksian1 [2.3K]2 years ago
7 0

Considering that we want to find a measure of center of the number of pages in the books, the correct option is:

B A box and whisker plot shows more information than a bar graph.

<h3>When to use a bar graph and a box and whisker plot?</h3>

  • It we are interest in the extremes of the distribution, that is, the smallest and largest amounts, we use a bar graph.
  • If we are interested in the central measures of the distribution, we use a box and whisker plot, as it contains more information.

In this problem, we want to find the average number of pages in the books, which is a measure of center, hence option B is correct.

More can be learned about a box and whisker plot at brainly.com/question/12343132

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George has a table that measures 1.5mx 2m x 0.3m. What is the<br> volume of his table?
Elina [12.6K]

Volume = Length * Width * Height

Volume of table = 1.5m * 2m * 0.3m

Answer : Volume of table = 0.9m³

6 0
2 years ago
Find the value of ( 1+cosA) (1-cosA)
Mandarinka [93]

Answer:

sin^2 A

Step-by-step explanation:

first expand the trigonometry

1(1-cosA)+cosA(1-cosA)

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from trigonometric identity sin^2 A + cos^2 A= 1

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3 0
2 years ago
Brainliest question please help please help me now plz
Kruka [31]

Answer:

Option A)   Inside the circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The radius is equal to the distance from the center to any point on the circle

the formula to calculate the distance between two points is equal to

d\sqrt{(y2-y1)^2+(x2-x1)^2 }

we have

A(-5,-8),M(-1,-3)

substitute the values

r=\sqrt{(-3+8)^{2}+(-1+5)^{2}}

r=\sqrt{(5)^{2}+(4)^{2}}

r=\sqrt{41}\ units

step 2

Find the distance from the center to point V

we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

If the distance from the center to point V is less than the radius, then the point V lie inside the circle

If the distance from the center to point V is greater than the radius, then the point V lie outside the circle

we have

A(-5,-8),V(-11,-6)

substitute in the formula

d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}

d=\sqrt{(2)^{2}+(-6)^{2}}

d=\sqrt{40}\ units

so

\sqrt{40}\ units< \sqrt{41}\ units

The distance from the center to point V is less than the radius

therefore

The point V lie inside the circle

Hope that helped :)

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