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mote1985 [20]
3 years ago
7

arun had 50 rupees if he had spent 3 by 5 of his money on an alarm clock how much money is he left with him

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
4 0

Answer:

total money=rupees 50

3/5 of 50= rupees 30

money he spent = rupees 30

money he's left with =50-30=20

<em>mark this as brainliest!!!!</em>

<em>pls</em><em> </em><em>follow</em><em> </em><em>me</em><em>!</em><em>!</em>

s2008m [1.1K]3 years ago
4 0

Answer:

Step-by-step explanation:

like u told me social studis

<3

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Klio2033 [76]

First part of question:

Find the general term that represents the situation in terms of k.

The general term for geometric series is:

a_{n}=a_{1}r^{n-1}

a_{1} = the first term of the series

r = the geometric ratio

a_{1} would represent the height at which the ball is first dropped. Therefore:

a_{1} = k

We also know that the ball has a rebound ratio of 75%, meaning that the ball only bounces 75% of its original height every time it bounces. This appears to be our geometric ratio. Therefore:

r=\frac{3}{4}

Our general term would be:

a_{n}=a_{1}r^{n-1}

a_{n}=k(\frac{3}{4}) ^{n-1}

Second part of question:

If the ball dropped from a height of 235ft, determine the highest height achieved by the ball after six bounces.

k represents the initial height:

k = 235\ ft

n represents the number of times the ball bounces:

n = 6

Plugging this back into our general term of the geometric series:

a_{n}=k(\frac{3}{4}) ^{n-1}

a_{n}=235(\frac{3}{4}) ^{6-1}

a_{n}=235(\frac{3}{4}) ^{5}

a_{n}=55.8\ ft

a_{n} represents the highest height of the ball after 6 bounces.

Third part of question:

If the ball dropped from a height of 235ft, find the total distance traveled by the ball when it strikes the ground for the 12th time. ​

This would be easier to solve if we have a general term for the <em>sum </em>of a geometric series, which is:

S_{n}=\frac{a_{1}(1-r^{n})}{1-r}

We already know these variables:

a_{1}= k = 235\ ft

r=\frac{3}{4}

n = 12

Therefore:

S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{1-\frac{3}{4} }

S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{\frac{1}{4} }

S_{n}=(4)(235)(1-\frac{3}{4} ^{12})

S_{n}=910.22\ ft

8 0
3 years ago
If one person recruits five people and each recruited person recruits 5 more, and so on, 15 cycles; how many people would that b
jek_recluse [69]

Answer:

y=5^x

5^15= 30517578125 people

Step-by-step explanation:

x=# of cycles= 15 cycles

y= #of people recruited = what we're figuring out

Plug in 15 for x in the equation y=5^x

y= 5^15= 30517578125 people

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3 years ago
Thirteen plus 5 times a number is no more than 30.<br> Step1: <br> Step2:<br> Step3: <br> Step4:
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Step 1: 13+5x=30
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2 years ago
ANSWER PLZZZZZZ!!!!!!!!!!!!!!!
meriva

Answer:

length=(3x-2)

Step-by-step explanation:

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5 0
3 years ago
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