The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
green=4/24 yellow=7/24 black=0/24 red, yellow=15/24
Step-by-step explanation:
Work shown above! Box a is 240 lbs Box b is 120 and Box c is 150 lbs hope this helps c:
Answer:
95
Step-by-step explanation:
80+(200 divided by 2)+(420 divided by 4)=285
285 divided by 3=95
Answer:
5/15
Step-by-step explanation:
