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blsea [12.9K]
3 years ago
9

со 7 және 5 12 4) 11 18 және 7 161. 1) 20 12; 7) 8 15 5 және 12 1 11 1 30 . және 5) 2) 24 және 12 via g 8) 7 30 1 және 12 1 3 жә

не 3) 16 12 6) 4. 21 13 және 28​
Mathematics
1 answer:
Vinil7 [7]3 years ago
5 0
Wha-

I don’t understand
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21/33 Marks
Marrrta [24]

Answer:

ooooooooooooooooooooooooooooooooo

Step-by-step explanation:

la de da de da la de da de deee sudennly you call my name an I lose my weight and I float up to the sky!

8 0
2 years ago
Find x<br><br> A. X = 23<br> B. X = 31<br> C. X = 62<br> D. X = 118
Scorpion4ik [409]

Answer:

A

Step-by-step explanation:

6x-20= 118

6x= 118 + 20

6x = 138

x = 138/6

x= 23

8 0
2 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
I have 7 hundreds blocks, 5 tens blocks, and 8 ones blocks. I use my blocks to model two 3-digit numbers. What could my two numb
kompoz [17]
Thought about it and theres a couple of others but i'm going to say 424-334
7 0
3 years ago
Elena is thinking about putting $200 in a savings account that earns 4% interest compounded semiannually. She wants to keep that
Nastasia [14]
I’m not 100% bc/ I learned this last semester, but I think it’s B. So sorry if I’m wrong. I think this bc/ 0.04 is the interest rate as a percent, 4 is the time, 200 is the amount of money, and the one shows that it is exponential growth.
8 0
3 years ago
Read 2 more answers
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