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2 years ago

In math, do you still distribute even the number is behind the parentheses?

2 answers:

8 0

The answer is YES!
You’re gonna have 10x+15+23
Then 10x + 38
And then you are doing next (2x+3) •5 + 23
So you have 2(5x+19)

taurus [48]2 years ago

7 0

Yes you would distribute the 5 typically following the steps of pemdas

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Use the following information to determine your answer: The length of a movie falls on a normal distribution. About 95% of movie

Elenna [48]

Answer:

$75= 119 -1.96 \sigma$

$\sigma = \frac{75-119}{-1.96}= 22.45$

And tha's equivalent to use this formula:

$163= 119 +1.96 \sigma$

$\sigma = \frac{163-119}{1.96}= 22.45$

Step-by-step explanation:

For this case the 95%of the values are between the following two values:

(75 , 163)

And for this case we know that the variable of interest X "length of a movie" follows a normal distribution:

$X \sim N( \mu, \sigma)$

We can estimate the true mean with the following formula:

$\mu = \frac{75+163}{2}= 119$

Now we know that in the normal standard distribution we know that we have 95% of the values between 1.96 deviations from the mean. We can find the value of the deviation with this formula:

$75= 119 -1.96 \sigma$

$\sigma = \frac{75-119}{-1.96}= 22.45$

And tha's equivalent to use this formula:

$163= 119 +1.96 \sigma$

$\sigma = \frac{163-119}{1.96}= 22.45$

4 0

3 years ago

The value of the 8 in 89.945 is how many times rhe value of the 8 in 763.186

trasher [3.6K]

Answer:

1000x

Step-by-step explanation:

8 0

3 years ago

Solve C = AB + D for B.

kirza4 [7]

5 0

3 years ago

Read 2 more answers

Hurry Please!

blagie [28]

I believe the answer should be 4 and 2

3 0

3 years ago

Invest $6,300 in two different accounts the first account paid 11% the second account paid 6% in interest at the end of the year

MAVERICK [17]

Answer: he invested $5300 at 11% and $1000 at 6%

Step-by-step explanation:

Let x represent the amount which he invested in the first account paying 11% interest.

Let y represent the amount which he invested in the second account paying 6% interest.

He Invest $6,300 in two different accounts the first account paid 11% the second account paid 6% in interest. This means that

x + y = 6300

The formula for determining simple interest is expressed as

I = PRT/100

Considering the first account paying 11% interest,

P = $x

T = 1 year

R = 11℅

I = (x × 11 × 1)/100 = 0.11x

Considering the second account paying 6% interest,

P = $y

T = 1 year

R = 6℅

I = (y × 6 × 1)/100 = 0.06y

At the end of the year, he had earned $643 in interest , it means that

0.11x + 0.06y = 643 - - - - - - - - - -1

Substituting x = 6300 - y into equation 1, it becomes

0.11(6300 - y) + 0.06y = 643

693 - 0.11y + 0.06y = 643

- 0.11y + 0.06y = 643 - 693

- 0.05y = - 50

y = - 50/ - 0.05

y = 1000

x = 6300 - y = 6300 - 1000

x = 5300

7 0

3 years ago