What is the answer to (-3b^4)^2/-12b^-9
1 answer:
You might be interested in
The <em>complement </em>C'<em> </em>of some set C is essentially the set we get when we remove all of the elements of C from the universal set U.
Here, our universal set contains all of the numbers 1-16, and the set C contains all of the odd numbers between 1 and 16. If we were to put both of these sets in roster form:
If we remove all of the elements of C from the universal set U, we're left with the complement of C, which contains all of the <em>even numbers </em>between 1 and 16:
Answer:
y = -2x - 4
Step-by-step explanation:
Formula is y = mx + b where m is the slope and b is the y-intercept
(1, -6) (-3, 2)
The slope is -2
y = -2x + b
So let's find b, insert 2 for y and -3 for x to find b
2 = -2(-3) + b
2 = 6 + b
Subtract 6 from both sides to get b alone
-4 = b
We found what b equals (the y-intercept), which is -4
So, the equation is y = -2x - 4
Hope this helps and pls do mark me brainliest:)