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AleksandrR [38]
1 year ago
14

an ice chest contains 8 cans of coke, 3 cans of pepsi, and 2 cans of 7up. what is the probability of pulling out an 7up

Mathematics
1 answer:
zalisa [80]1 year ago
3 0

The probability of pulling out an 7up from the ice chest that contains the different drinks is 2/13.

<h3>What is the probability?</h3>

Probability determines the odds that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The probability of pulling out an 7up = number of 7ups / total number of drinks

2/(8 + 3 + 2)

2/13

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

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Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

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 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

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