Answer: This is late but they can expect to pay b.)56.25%
Answer:
Y=59 Z=93
Explanation:
To find Z, you have to know the line is equal to 180 degrees. You then subtract 180-87=93 that’s how you get Z. Then with that you know that 34+Y is going to equal 93 because they are across from each other. I forgot what that property is called, but yeah. Then you subtract 93-34=59 there you go hope that helps :)
Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277
Lol, wydm???????????????????
Answer:
yes
Step-by-step explanation:
