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2 years ago

Simplify the expression 7 times 3g

Mathematics

2 answers:

Naddika [18.5K]2 years ago

8 0

7x3=21 and then there’s g so 21g

yKpoI14uk [10]2 years ago

4 0

The answer is 21g hope this helps :)

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Find the area of the circle.

juin [17]

Answer:

See Explanation Below

Step-by-step explanation:

Your question isn't clear; However, I'll solve in two ways

1. Diameter = 14 cm

2. Radius = 14 cm

When Diameter = 14 cm

Given

$Area = \pi r^2$

$Diameter = 14cm$

Required

Calculate the area of the circle

First, the radius has to be solved;

$Radius = \frac{1}{2} Diameter$

$Radius = \frac{1}{2} * 14cm$

$Radius = 7cm$

Using the given formula;

The area is as follows

$Area = \pi r^2$

$Area = 3.14 * 7^2$

$Area = 3.14 * 49$

$Area = 153.86cm^2$

When Radius = 14 cm

Given

$Area = \pi r^2$

$Radius = 14cm$

Required

Calculate the area of the circle

Using the given formula;

The area is as follows

$Area = \pi r^2$

$Area = 3.14 * 14^2$

$Area = 3.14 * 196$

$Area = 615.44cm^2$

7 0

3 years ago

Can someone plz help me

Sati [7]

Answer:

One point greater than the last grade

Step-by-step explanation:

1. First off, N is the variable, so that means it can be any number, and when it uses the word greater, it means to ADD another number, which means one point greater.

6 0

2 years ago

Read 2 more answers

How to solve logarithmic equations as such

Serga [27]

$\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5$

$\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}$

5 0

3 years ago

L'Airbus A380 consomme approximativement 15 600 litres de kérosène à

sasho [114]

Answer:

7 800 pour 1/2 heure

Step-by-step explanation:

15 600/2=7 800

7 0

2 years ago

Help&EXPLAIN Don’t use for points or will be reported and I’ll take the points back

ella [17]

Answer:

x = 60°

Step-by-step explanation:

since, the triangles are complementary the sum of their measures will be 90°

now,

=》30° + x = 90°

=》x = 90° - 30°

=》x = 60°

4 0

2 years ago