Given:
The cost of adults ticket = $18
The cost of children's ticket = $8.25
Total tickets = 2300
Total revenue = $30,168.
To find:
The number of children and number of adults attended the zoo that day.
Solution:
Let x be the number of children and y be the number of adults.
Equation for tickets: 
...(i)
Equation for revenue: 
...(ii)
Plot the graphs of the given equations on a coordinate plane as shown below.
From the graph it is clear that the graph of both equations intersect each other at (1148,1152).
It means the number of adults is 1148 and the number of children is 1152.
It can be solved algebraically as shown below:
Substitute the value of y in (ii) from (i).
Divide both sides by 9.75.
Putting in (i), we get
Therefore, the number of adults is 1148 and the number of children is 1152.
The system of equations best represents the number of apples a and the number of garonia bars g be a+b=60, 0.75x+0.15y=21.
Given that cost of 1 apple is $0.75, cost of 1 gargonia bars be $0.15 ,total things are 60 and total money paid be $21.
Equation is relationship between two or more variables expressed in equal to form. Equation of two variables look like ax+by=c. It may be a linear equation,quadratic equation, cubic equation.
Because we have been told that there are 60 total things and a represents the number of apples and g represents number of garonia represents the number of garonia bars.
a+b=60--------1
Money paid by consumers is cost per units*number of units
So,
0.75a+0.15b=21
Hence the system of equations best represent the number of apples and the number of garonua bars g are a+b=60, 0.75a+0.15b=21.
Learn more about equations at brainly.com/question/2972832
#SPJ4
Let x represent his daughter age
Then the expression: 5x - x = 36
Solve for x: 4x = 36
Then x = 36/4 = 8
The daughter is 8 years old
Jamari is 40 years old
Divide 56.5 by 2 and c what u get
(x+6)^2=0 is the answer i think
