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MariettaO [177]
3 years ago
11

Why does (x-2)^2+9=0 have no real solutions?

Mathematics
1 answer:
alex41 [277]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Given

(x - 2)² + 9 = 0 ( subtract 9 from both sides )

(x - 2)² = - 9  ( take the square root of both sides )

x - 2 = ± \sqrt{-9}

\sqrt{-9} yields no real solutions

There is no real number when multiplied by itself gives - 9

In fact the solutions to \sqrt{-9} are said to be imaginary, that is ± 3i

where i = \sqrt{-1}

If interested investigate further.

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Substitution doesn't work for this, but elimination does.

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