Answer:
check photo for detailed analysis
Which of the functions below could possibly have created this graph?
2 answers:
Answer:
The function that could possibly have created this graph is:
Step-by-step explanation:
As we know that any odd degree polynomial has odd number of real zeros since the complex zero always exist in pair.
Here in the graph we see that there are 4 real zeros.
Hence, the polynomial can't be a odd degree polynomial.
Hence, option: B and Option: C are discarded.
So, we are left with choice A and D i.e. a even polynomial.
Also as we could see that the end behavior of the graph satisfy:
as x→ -∞ F(x) → -∞
Also when x → ∞ then F(x) → -∞
Hence, the even degree polynomial must have a negative leading coefficient.
Hence, option: D is also discarded.
Hence, option: A is the answer.
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Hope that helps!
In the polygon ABCD, the production of point A' and point D' is (-2,-2) and (4,-2) respectively.
<h3>What is the transformation rule?</h3>In coordinate planes, the rule of transformation involves interchanging the x and y values on the plane such that:
where;
- k = scale factor
From the given information:
- The scale factor = 2
- the origin as a center of dilation for image vertices = (0, 0)
Now, using the coordinate vertices:
- A = (-1, -1)
- D = (2, -1)
The corresponding coordinate of the image vertices is as follows:
A(-1,-1) → A'(2 × (-1), 2 × (-1))
A' = (-2,-2)
D(2,-1) → A'(2 × (2), 2 × (-1))
D' = (4,-2)
Learn more about the transformation rule in coordinate planes here:
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