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2 years ago

Find an equation of the line with the given slope that passes through the given point Write the equation in the form Ax + By = C

Mathematics

1 answer:

guajiro [1.7K]2 years ago

8 0

Answer:

$8x + y = - 52$

Step-by-step explanation:

m= -8

p (-6,-4)

Formula for equation of a logbook passing through to points:

$y - y1 = m(x - x1)$
where y1= -4 and x1= -6
$y - ( - 4) = - 8(x - ( - 6)) \\ y + 4 = - 8(x + 6) \\ y + 4 = - 8x - 48 \\ 8x + y = - 52$

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3 years ago

The path of a volley ball thrown over a net is modeled with the function A(x) = -0.02x2 + 0.6x + 5, where x is

LiRa [457]

Answer:

The ball travel horizontally 37 feet before it hits the ground

Step-by-step explanation:

we have

$A(x)=-0.02x^2+0.6x+5$

where

x ----> is the horizontal distance in feet

A ---> is the altitude of the ball, in feet.

we know that

When the ball hit the ground, the altitude of the ball is equal to zero

For A(x)=0

$-0.02x^2+0.6x+5=0$

solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.02x^2+0.6x+5=0$

$a=-0.02\\b=0.6\\c=5$

substitute in the formula

$x=\frac{-0.6\pm\sqrt{0.6^{2}-4(-0.02)(5)}} {2(-0.02)}$

$x=\frac{-0.6\pm\sqrt{0.76}} {-0.04}$

$x=\frac{-0.6\pm0.87} {-0.04}$

$x=\frac{-0.6+0.87} {-0.04}=-6.75$

$x=\frac{-0.6-0.87} {-0.04}=36.75$

therefore

The ball travel horizontally 37 feet before it hits the ground

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3 years ago