The answer is the Parallelogram
Yes hope it helps!!!!!!!!
Answer:
Wrong. It equals 2560.
Step-by-step explanation:
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Answer:
6.5 seconds
Step-by-step explanation:
Keep in mind that when
, this is the same height for both when the model rocket takes off and lands, so when the rocket lands, time is positive. Thus:

So, the amount of seconds that the model rocket stayed above the ground since it left the platform is 6.5 seconds
Answer:
The answer is a
Step-by-step explanation:
Using point (0,0) and (3,-9)
Slope of the line = -9-0/3-0 = -9/3 = -3
Equation of the line using point (0,0)
y - 0 = -3(x -0)
y= -3x
Hope this helps.