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Ronch [10]
4 years ago
13

Solve 2^x=32 and rewrite this equation in a logarithmic form.

Mathematics
1 answer:
snow_tiger [21]4 years ago
4 0

{2}^{x}   = 32  \\  log( {2}^{x} )  =  log(32)  \\ xlog2 =  log(32)  \\ x =  \frac{ log(32) }{2}  \\ x = 5
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