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lana66690 [7]
3 years ago
9

GCF of the numbers 15 and 27

Mathematics
2 answers:
balandron [24]3 years ago
6 0
Three would be your answer :)
rusak2 [61]3 years ago
6 0
The gcf of 15 and 27 will be 3.
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HELP!! ASAP PLEASE!! WILL GIVE BRAINLIEST!!
patriot [66]

Answer:

6^-4 ÷ 3^-4

6^-4/3^-4

Since their powers are negative

Flip them both so the negative index is lost.

It now becomes

3^4/6^4

81/1296

=1/16

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3 years ago
Please help with these two questions and give an accurate answer. I will mark u the brainiest. Sinking Rivers charges two hundre
Soloha48 [4]

Answer:

Step-by-step explanation:

First one is 200 dollars for insurance which will be the constant and 15 dollars an hour which means the equation will be;

C = 15h +200 (Sinking Rivers)

Second one is $30 an hour and $110 for insurance which is the constant so he equation is;

C = 30h + 110 (Floating Down The Stream)

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Z = -3x +5y<br> Minimum value of z?
NeTakaya

Answer:

minimum value of z is 0

Step-by-step explanation:

if x and y both equal zero, then the value of z is zero, which is your answer.

7 0
2 years ago
The probability that a person in the United States has type B​+ blood is 10%. Four un-related people in the United States are se
marysya [2.9K]

Answer:

a. 0.0001

b. 0.6561

c. 0.3439

d. B. The event in part​ (a) is unusual because its probability is less than or equal to 0.05.

Step-by-step explanation:

a. # We are given that the probability that a person in the United States has Type B+ blood = 0.10. Also we are told that four unrelated people in the United States are selected at random.

#We have to find here the probability that all four have type B+ blood.

Since the events are independent, we have :

Probability that all four have B+ blood  = 0.10 x 0.10x 0.10x0.10

                                                                                       = 0.0001

Therefore, the probability that all four have type B+ blood is 0.0001

b. We have to find the probability that none have B+ blood. Using the complementary law of probability we have:

Probability that blood type is not B+ = 1 - 0.10= 0.90                                                                        

Therefore, the probability that none have B+ blood

= 0.90 x 0.90 x 0.90x0.90=0.6561

Therefore, the probability that none have B+ blood is 0.6561

c. We have to find the probability that at least one of the four have B+ blood.

#The probability that at least one of the four have B+ blood = 1 -  Probability that none have B+ blood type

=1-0.6561=0.3439

Therefore,the probability that at least one of the four has type B+ blood is 0.3439

d. An event is considered unusual if the probability of the event is small or less than 0.05 . We note that event a is the only small probabilty and is less than 0.05.

-a is thus considered unusual(the rest are all usual events)

                                                                                                                 

6 0
2 years ago
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