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lana66690 [7]
3 years ago
9

GCF of the numbers 15 and 27

Mathematics
2 answers:
balandron [24]3 years ago
6 0
Three would be your answer :)
rusak2 [61]3 years ago
6 0
The gcf of 15 and 27 will be 3.
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GIVING BRANLIEST!!!
lidiya [134]

Answer:

I believe it's (6,10).

5 0
3 years ago
I need help plss!! I don’t understand
MA_775_DIABLO [31]

Since it says what the area of the circle is, you need to work the problem backwards from finding the area. So it would be 100 ÷ 3.14 = 31.84 that is the radius. Next you need to find the diameter, so 31.84 × 2 = 63.68. Now you multiply 63.68 × 3.14 = 199.95, round that to 200, divide 200 ÷ 2 = 100 ÷ 2 = 50 miles

Answer= 50 miles

4 0
3 years ago
You bicycle along a straight flat road with a safety light attached to one foot. Your bike moves at a speed of 15 km/hr and your
Viefleur [7K]

Answer:

a)

x(t) = ( 4.167 t + 0.2 cos (2πt))

y(t) = ( 0.3 - 0.2 sin  (2πt))

b) the  foot have to be 3.32 rev/sec faster

Step-by-step explanation:

Given that:

the speed of the bike = 15 km/hr = 15 × 1000/3600 (m/sec) = 4.167 m/sec

radius of the circle when the foot moves = 20 cm = 0.2 m

radius of the circle above the ground = 30 cm = 0.3 m

Let assume that:

x(t)  should represent the vector along the horizontal moment

y(t) should be the vector along the vertical moment

The initial component will be ( 0, 0.3)

We know that the radius of the circle is given as 0.2 m, So the vector of the circle can be written as (0.2 cos t , 0.2 sin t )

Also, the foot makes one revolution in a second, definitely the frequency of the revolution = 1 and the vector for the circle is ( 0.2 cos (2πt), -0.2 sin  (2πt)), due to the fact that the foot moves clockwise.

Thus, adding all the component together ; we have:

(x(t), y(t)) = (0,0.3)+(4.167 t , 0)+(0.2 cos (2πt), -0.2 sin  (2πt))

(x(t), y(t)) = (4.167 t + 0.2 cos (2πt), 0.3 - 0.2 sin  (2πt))

Hence; the parametric equations are:

x(t) = ( 4.167 t + 0.2 cos (2πt))

y(t) = ( 0.3 - 0.2 sin  (2πt))

b)

The linear speed of rotation is :

15km/hr = 15 × 100, 000/3600 (cm/sec)

             = 416.7 cm/sec

The rotational frequency is :

= 416.7/2πr

= 416.7/2(3.14 × 20)

= 3.32 rev/sec

Hence, the  foot have to be 3.32 rev/sec faster in rotating if an observer standing at the side of the road sees the light moving backward.

4 0
3 years ago
Read 2 more answers
Make vthe subjject of the formulaE=mvsquare/ 2<br>find the value of v when m =2 and E=64​
Maksim231197 [3]

E=mv²

divide both sides by m

E/m=v²

square root both sides

v=√E/m

m=2,E=64

v=√64/2

v=9/√2

6 0
3 years ago
At which approximate x-value are these two equations equal? A. 0. 5 B. 0. 8 C. 1. 2 D. 1. 4.
Alinara [238K]

Answer:

What are the two equations?

Step-by-step explanation:

Once u answer that I'll edit this and answer ur question :)

5 0
2 years ago
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