All categories

2 years ago

Can anybody help me...

Mathematics

1 answer:

asambeis [7]2 years ago

4 0

Answer: The 3 angles shown need to equal 180 degrees

x = 180 - 75 - 65

x = 40 degrees

Step-by-step explanation:

I had someone help out with this one...hope this helps u out have a good rest of ur day!!!!!

You might be interested in

Can someone please help me solve 1-|1/3q-5|=-6

FrozenT [24]

Hello,

2 cases:

if 1/3*q-5>0 then

|1/3*q-5|=1/3*q-5
1-|1/3*q-5|=-6
1-(1/3*q-5)=-6
1-1/3*q+5=-6
6-1/3*q=-6
-1/3*q=-12
q=36

else

|1/3*q-5|=-(1/3*q-5)
1-|1/3*q-5|=-6
1+(1/3*q-5)=-6
1+1/3*q-5=-6
-4+1/3*q=-6
1/3*q=-2
q=-6

4 0

3 years ago

Brett has a $30 online gift certificate. He plans to buy as many books as he can. The cost of each book is $4. There is also a s

kkurt [141]

Answer:

7 books

Step-by-step explanation:

make an equation

x = # of books each book is $4 so its 4x

the shipping fee no matter how many books he buys will be $2 so it's just 2

the equation looks like this:

4x + 2 = 30

we set equal to 30 cuz he can't spend more than $30

solve for x

4x = 30 -2

4x = 28

x = 7

Brett can buy no more than 7 books.

7 0

3 years ago

GIVING BRAINLIEST FOR BEST ANSWER!

Setler79 [48]

7 / 7 = 1

3 + 1 = 4

4 + 3 and 1 / 3 = 7 and 1 / 3

6 0

2 years ago

Read 2 more answers

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0

4 years ago

What is the solution to the equation

FinnZ [79.3K]

The answer is -7 :) hope this helps

4 0

3 years ago

Can anybody help me...​

Can anybody help me...