In order to be differentiable everywhere, 
must first be continuous everywhere, which means the limits from either side as 
must be the same and equal to 
. By definition, 
, and
so we need to have 
.
For to be differentiable at 
, the derivative needs to be continuous at , i.e.
We then need to have
Then
1. Substitute the function f(x) into x in g(x)
2. Simply your results in 1. now you have (g o f)(x)
3. Now substitute 6 into your results in 2 to get (g o f)(6)
Answer:
is the sum 78 or 7,878 (i.e. was there a stutter)?
In any event, this sum must be even, so 3 consecutive even integers would be n, n+2 & n+4 whose sum is 3n + 6.
Set that to either 78 or 7878, whichever is intended, & solve for n. If 78 is their grand total, then those 3 consecutive even numbers have to be 24, 26 & 28.
No stress! Just logic! Keep the faith!
Step-by-step explanation:
Tyler moved 180 kilograms
30-12=18 so 18×2=36 36×5=180
