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MArishka [77]
2 years ago
6

In which data set is the mean less than the median?

Mathematics
2 answers:
stepan [7]2 years ago
7 0
The last one. the mean is the average and the median is the middle point in the data set. the average is less than the middle point.
maks197457 [2]2 years ago
4 0
It is the 4th data set.
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Which factor pair does not belong to 36
vekshin1

Answer:

36 is a composite number as it has factors other than 1 and itself. Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. Pair factors of 36 are (1, 36), (4, 9), (6, 6), (12, 3), and (18, 2). 1 is a factor of every number.

7 0
2 years ago
(3x²+3x+5)+(7x²-9x=8)=10x²-12x=13
Brilliant_brown [7]

The value of x is equal to -5/6

To solve this question, we have to add two polynomials together. The polynomials are;

  • 3x^2+3x+5
  • 7x^2-9x=8
<h3>Addition of Polynomials</h3>

This involves adding of two or more different polynomials together. The polynomials adding together are or must be of the same degree. i.e x^2 must add to another coefficient of x^2 and x^3 adds to another coefficient of x^3 and so on.

In this given question, let's add the polynomials together.

(3x^2+3x+5) + (7x^2-9x = 8\)\\3x^2 + 7x^2 + 3x-9x+5-8 =10x^2-6x-3

Now, let's equate this with the last polynomial given

10x^2-6x-3=10x^2-12x-13\\10x^2-10x^2-6x+12x-3+13\\0+12x+10\\12x=-10

Let's solve for x

12x=-10\\x=-\frac{10}{12}\\x = -\frac{5}{6}

The value of x is equal to -5/6

Learn more on addition of polynomials here;

brainly.com/question/4142886

8 0
2 years ago
From the sun of 4+3x and 5-4x+2x2⬅subtract the sum of 3x2-5x and -x2⬅+2x+5
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3 years ago
jerry climbed 210 feet in elevation. He then went down 300 feet. What integer represents his total change in elevation
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210-300=-90

Step-by-step explanation:hope this helps plz mrk me brainliest

3 0
3 years ago
What is 3/5 divided by 2 1/2 by the lowest quotient
Brilliant_brown [7]

Answer:

<h2>\frac{6}{25}</h2>

Step-by-step explanation:

<h3>\frac{3}{5} ÷ \frac{5}{2} = \frac{3}{5} ÷ \frac{2}{5} = \frac{6}{25}</h3>
7 0
3 years ago
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