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2 years ago

What are a domain and range?

Mathematics

1 answer:

Nikolay [14]2 years ago

5 0

Answer:

The domain and range of function is the set of all possible inputs and outputs of a function respectively.

The domain and range of a function y = f (x) is given as domain= {x ,x∈R }, range= {f (x), x∈Domain}.

The domain and range of any function can be found algebraically or graphically.

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rafeal counted a total of 40 white cars and yellow cars. there were 9 times as many white cars as yellow cars. how many white ca

liberstina [14]

360 is the anwer because i multipled 40 white cars by 9 times yellow car to get answer 40×9=360

5 0

3 years ago

Read 2 more answers

Paper clips are sold in boxes of 1000.

belka [17]

Answer:

6.5%

Step-by-step explanation:

1000 in a box and he orders 5 boxes.

1000x5= 5000

So he orders 5000 paper clips

1 box is £15.40 and he order 5, so £15.40x5= £77

£77 is between £55 and £79.99 so he will get 6.5% discount.

After the discount he will pay £71.99

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3 years ago

60=F(15) <br><br> Please solve this and show work, please

Lubov Fominskaja [6]

Answer:

f = 4

Step-by-step explanation:

60= 15f

divide both side by 15

f = 4

3 0

3 years ago

A bag contains 63 marbles, some red and some green. The ratio of red marbles to green

Nikolay [14]

Answer:

45 green marbles

Step-by-step explanation:

6 0

3 years ago

Find the equation of a line perpendicular to y - 12 = 2x – 8 that passes through the point (2, 3). (answer in slope-intercept fo

Alla [95]

Answer:

$\displaystyle y=-\frac{1}{2}x+4$

Step-by-step explanation:

<u>Equation of a Line</u>

We can find the equation of a line by using two sets of data. It can be a pair of ordered pairs, or the slope and a point, or the slope and the y-intercept, or many other combinations of appropriate data.

We are given a line

$y - 12 = 2x -8$

And are required to find a line perpendicular to that line. Let's find the slope of the given line. Solving for y

$y = 2x +4$

The coefficient of the x is the slope

$m=2$

The slope of the perpendicular line is the negative reciprocal of m, thus

$\displaystyle m'=-\frac{1}{2}$

We know the second line passes through (2,3). That is enough information to find the second equation:

$y-y_o=m'(x-x_o)$

$\displaystyle y-3=-\frac{1}{2}(x-2)$

Operating

$\displaystyle y=-\frac{1}{2}(x-2)+3$

Simplifying

$\displaystyle y=-\frac{1}{2}x+4$

That is the equation in slope-intercept form. Intercept: y=4

8 0

3 years ago