Quadrant IV
at quadrant IV, sinA is negative value while cosA is positive value
2n - 1 - -7n + 2 You combine like terms with subtracting
2n - 7n = -5n
-1 - 2 = -3
So -7n + 2 - 2n - 1 = -5n - 3
Answer:
10 miles.
Step-by-step explanation:
Let x be the number of miles on Henry's longest race.
We have been given that Henry ran five races, each of which was a different positive integer number of miles.
We can set an equation for the average of races as:
As distance covered in each race is a different positive integer, so let his first four races be 1, 2, 3, 4.
Now let us substitute the distances of 5 races as:
Let us multiply both sides of our equation by 5.
Let us subtract 10 from both sides of our equation.
Therefore, the maximum possible distance of Henry's longest race is 10 miles.
Answer:
The umbrella will fit in, but there will be a lot of extra room.
Step-by-step explanation:
Remember the Pythagorean theorem:
x^(2) + y^(2) = n^(2)
where "x" and "y" are the legs of the right triangle and "n" is the hypotenuse
In this problem it is given that the sides (legs) are:
38in, and 24in
and diagonally across is 29in
so the hypotenuse is 29in
therefore we can form the equation:
38^(2) + 24^(2) = 29^(2)
without solving it is clear that
38^(2) + 24^(2) > 29^(2)
because 38 is a leg, but it is greater than 29, which means that 38 - 24 - 29 is not a Pythagorean triple,
but because 38 > 29, then the 29 in umbrella will fit into the suitcase, but it will not be a snug fit, there will be a lot of extra room
The lowest term would be 16.6
