Answer:
imma go wit B. I mean thats my guess
By shooting the question correctly and exactly specifying which question you are referring to
Answer:
Option B is correct.
Step-by-step explanation:
The distance formula used is:

We need to find distance between origin and other point (3,-4,5)
Origin is: (0,0,0)
x₁ = 0, y₁ = 0, z₁ =0 and x₂= 3, y₂= -4 and z₂ = 5
Putting values in the distance formula we get:

The Distance from the origin to the point (3, −4, 5) is 7 units.
Option B is correct.
<span>Lets calculate an example:
Say, .001% of tires that come from the factory are bad. There is a 1/1000 chance that for any given tire randomly selected from the warehouse that a defect will be present. Each tire is a mutually exclusive independently occurring event in this case. The probability that a single tire will be good or bad, does not depend on how many tires are shipped in proportion to this known .001% (or 1/1000) defect rate.
To get the probability in a case like this, that all tires are good in a shipment of 100, with a factory defect rate of .001%, first divide 999/1000. We know that .999% of tires are good. Since 1/1000 is bad, 999/1000 are good. Now, multiply .999 x .999 x .999..etc until you account for every tire in the group of 100 shipped. (.999 to the hundredth power)
This gives us 0.90479214711 which rounds to about .90. or a 90% probability.
So for this example, in a shipment of 100 tires, with a .001% factory defect rate, the probability is about 90 percent that all tires will be good.
Remember, the tires are mutually exclusive and independent of each other when using something like a factory defect rate to calculate the probability that a shipment will be good.</span>
Answer:
Question 21: C.
Question 22: I.
Question 23: E.
Question 24: B.
Step-by-step explanation:
#21: The first statement is presented in the "Given" section.
#22: Since the reflexive property states that anything is equal to itself, BC ≅ BC.
#23: C being the midpoint of AD means that C is the same distance from both point A and point D. This then means that AC ≅ CD.
#24: AB ≅ DB due to the given, BC ≅ BC (since it's the same side), and we've proven that AC ≅ CD using a midpoint. We've proven <em>all three sides</em> on the two triangles to each other are congruent. This means that we've proven the triangles using SSS, which is B.