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12345 [234]
2 years ago
13

Which of the following statements are TRUE? SELECT ALL THAT APPLY.

Mathematics
1 answer:
Reil [10]2 years ago
5 0

Answer:

b d e a im not fore sure tho

Step-by-step explanation:

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When did my mom chop up my glizzy<br><br> A:2015<br> B:2017<br> C:2018<br> D:2020
Artist 52 [7]

Answer:

imma go wit B. I mean thats my guess

5 0
3 years ago
How do you solve this ?
kakasveta [241]
By shooting the question correctly and exactly specifying which question you are referring to
4 0
3 years ago
What is the approximate distance from the origin to the point (3, −4, 5)? Round to the nearest unit. 4 units 7 units 8 units 9 u
Dafna11 [192]

Answer:

Option B is correct.

Step-by-step explanation:

The distance formula used is:

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2}

We need to find distance between origin and other point (3,-4,5)

Origin is: (0,0,0)

x₁ = 0, y₁ = 0, z₁ =0 and x₂= 3, y₂= -4 and z₂ = 5

Putting values in the distance formula we get:

d=\sqrt{(3-0)^2+(-4+0)^2+(5-0)^2}\\d=\sqrt{(3)^2+(-4)^2+(5)^2}\\d=\sqrt{9+16+25}\\d=\sqrt{50}\\d=7

The Distance from the origin to the point (3, −4, 5) is 7 units.

Option B is correct.

3 0
3 years ago
F 100 tires are randomly selected for shipment to an outlet what is the probability that they are all​ good?
sergeinik [125]
<span>Lets calculate an example: Say, .001% of tires that come from the factory are bad. There is a 1/1000 chance that for any given tire randomly selected from the warehouse that a defect will be present. Each tire is a mutually exclusive independently occurring event in this case. The probability that a single tire will be good or bad, does not depend on how many tires are shipped in proportion to this known .001% (or 1/1000) defect rate. To get the probability in a case like this, that all tires are good in a shipment of 100, with a factory defect rate of .001%, first divide 999/1000. We know that .999% of tires are good. Since 1/1000 is bad, 999/1000 are good. Now, multiply .999 x .999 x .999..etc until you account for every tire in the group of 100 shipped. (.999 to the hundredth power) This gives us 0.90479214711 which rounds to about .90. or a 90% probability. So for this example, in a shipment of 100 tires, with a .001% factory defect rate, the probability is about 90 percent that all tires will be good. Remember, the tires are mutually exclusive and independent of each other when using something like a factory defect rate to calculate the probability that a shipment will be good.</span>
4 0
3 years ago
PLEASE SOMEONE HELP ME WITH THESE MATH QUESTIONS!!! *VERY URGENT* *IF YOU ANSWER CORRECTLY, YOU'LL GET 10 POINTS!*
Tasya [4]

Answer:

Question 21: C.

Question 22: I.

Question 23: E.

Question 24: B.

Step-by-step explanation:

#21: The first statement is presented in the "Given" section.

#22: Since the reflexive property states that anything is equal to itself, BC ≅ BC.

#23: C being the midpoint of AD means that C is the same distance from both point A and point D. This then means that AC ≅ CD.

#24: AB ≅ DB due to the given, BC ≅ BC (since it's the same side), and we've proven that AC ≅ CD using a midpoint. We've proven <em>all three sides</em> on the two triangles to each other are congruent. This means that we've proven the triangles using SSS, which is B.

7 0
3 years ago
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