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3 years ago

Will fan and medal! Identify the transformations that describe the graph of an even function select all that apply.

1 answer:

4 0

2 is the only right answer. If it has right/left symmetry, then f(-x) = f(x), meaning it's even.
extra info: 3 and 4 are the same thing
5 works for odd functions (like sin(x))

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All of the following expressions represent the sum of n and itself, except _____.

DochEvi [55]

N^2 because 2n is the same as n+n, but n^2 is the same as the product of n and n

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3 years ago

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What is the final velocity of a runner who is accelerating at 2 feet per second squared for 3 seconds with an initial velocity o

Tatiana [17]

<span>a= 2 ft/s^2 t=3 s vi=4 ft/s vf=? One can use the kinematic equation: vf=vi+at vf=(4 ft/s)+(2 ft/s^2)(3 s)= (4 ft/s)+(6 ft/s)=10 ft/s</span>

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3 years ago

Subtract 5x−2 from −3x+4 .

Elanso [62]

Answer:

-8x +6

Step-by-step explanation:

5x−2 from −3x+4 .

This means take the 2nd number and subtract the 1st

-3x +4

-( 5x -2)

----------------

Distribute the negative sign

-3x +4

- 5x +2

----------------

-8x +6

5 0

3 years ago

A box contains 4 oranges, 9 apples, and 3 pears. Liliana selects a piece of fruit from the box at random.

gizmo_the_mogwai [7]

Answer is 7/16.
Add number of fruit total to get denominator. Add number of oranges and pears to get numerator.

8 0

3 years ago

Gravel is being dumped from a conveyor belt at a rate of 15 ft3/min, and its coarseness is such that it forms a pile in the shap

gayaneshka [121]

Answer:

0.13 ft/min

Step-by-step explanation:

We are given that

$\frac{dV}{dt}=15ft^3/min$

We have to find the increasing rate of change of height of pile when the pile is 12 ft high.

Let d be the diameter of pile

Height of pile=h

d=h

Radius of pile,r= $\frac{d}{2}=\frac{h}{2}$

Volume of pile= $\frac{1}{3}\pi r^2 h=\frac{1}{12}\pi h^3$

$\frac{dV}{dt}=\frac{1}{4}\pi h^2\frac{dh}{dt}$

h=12 ft

Substitute the values

$15=\frac{1}{4}\pi(12)^2\frac{dh}{dt}$

$\frac{dh}{dt}=\frac{15\times 4}{\pi(12)^2}$

$\frac{dh}{dt}=0.13ft/min$

7 0

3 years ago