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ella [17]
3 years ago
12

Half of a liter is equal to 16.91 ounces how many ounces are there in 3 liters

Mathematics
2 answers:
Alexeev081 [22]3 years ago
8 0
If one half a liter is 16.91 ounces, that means one liter is equal to 33.82 liters. If you multiply that by three, that gets you to 101.46 ounces in 3 liters!

Answer: 101.46 ounces in three liters
Zanzabum3 years ago
6 0

Let, liter =l & Ounces =O

l/2 = 16.91O

l = 33.82O

Multiply both sides by 3,


3l = 101.46O

So, there are 101.46 Ounces in a liter. VOTE ME BRAINLIEST


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Answer:

its 16

Step-by-step explanation:

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In a survey, the planning value for the population proportion is . How large a sample should be taken to provide a confidence in
tatuchka [14]

Answer:

n=350

Step-by-step explanation:

Notation and definitions

n random sample taken  (variable of interest)

\hat p=0.35 estimated proportion  (value assumed)

p true population proportion

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Me=0.05 (value assumed)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.586  

And rounded up we have that n=350

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