The foci of the hyperbola with equation 5y^2-4x^2=20 will be given as follows:
divide each term by 20
(5y^2)/20-(4x^2)/20=20/20
simplifying gives us:
y^2/4-x^2/5=1
This follows the standard form of the hyperbola
(y-k)²/a²-(x-h)²/b²=1
thus
a=2, b=√5 , k=0, h=0
Next we find c, the distance from the center to a focus.
√(a²+b²)
=√(2²+(√5)²)
=√(4+5)
=√9
=3
the focus of the hyperbola is found using formula:
(h.h+k)
substituting our values we get:
(0,3)
The second focus of the hyperbola can be found by subtracting c from k
(h,k-c)
substituting our values we obtain:
(0,-3)
Thus we have two foci
(0,3) and (0,-3)
3t+10=16
-10. -10
3t=6
/3. /3
T=2
Answer:
Gianna ran 40 miles over the course of 17 weeks.
Step-by-step explanation:
20 miles in the first week.
5% increase each week.
17 weeks.
1 mile increase each week.
17 mile increase over the course of 17 weeks.
37 miles over the course of 17 weeks.
Round 37 to the nearest whole number.
18.84 because circumference is 2piR so 2(3)(3.14)= 18.84
Answer:
80/160
Step-by-step explanation:
so basically...
50 is half of 100
so then you look at it and your like welp if its half then ur going to have to do half for 80
so 80 x 2= 160
and for A can you please show the options or at least tell me
