Question

Consider the following program written in C syntax:

Answer 1

The values of the variables value and list after each of the three calls to

swap are:

• value = 2 and  list[5] = {1, 3, 5, 7, 9};
• value = 2 and  list[5] = {3, 1, 5, 7, 9};
• value = 2 and  list[5] = {3, 1, 5, 7, 9};

How to determine the values of variable value and the list?

1. Passed by value

In this case, the values of the actual arguments remain unchanged; So the variable value and the list would retain their initial values

The end result is:

value = 2 and  list[5] = {1, 3, 5, 7, 9};

2. Passed by reference

With pass by reference, the arguments are changed.

Given that

value = 2 and  list[5] = {1, 3, 5, 7, 9};

The value of variable value is swapped with list[0].

So, we have:

value = 1 and  list[5] = {2, 3, 5, 7, 9};

Then list[0] and list[1] are swapped

So, we have:

value = 1 and  list[5] = {3, 2, 5, 7, 9};

Lastly, value and list[value] are swapped

So, we have:

value = 2 and  list[5] = {3, 1, 5, 7, 9};

The end result is:

value = 2 and  list[5] = {3, 1, 5, 7, 9};

3. Passed by value-result

Since there is no loop in the program, the pass by value-result has the same output as the pass by reference.

So, the end result is:

value = 2 and  list[5] = {3, 1, 5, 7, 9};

Read more about C syntax at:

brainly.com/question/15705612