Answer:
Flowchart of an algorithm (Euclid's algorithm) for calculating the greatest common divisor (g.c.d.) of two numbers a and b in locations named A and B. The algorithm proceeds by successive subtractions in two loops: IF the test B ≥ A yields "yes" or "true" (more accurately, the number b in location B is greater than or equal to the number a in location A) THEN, the algorithm specifies B ← B − A (meaning the number b − a replaces the old b). Similarly, IF A > B, THEN A ← A − B. The process terminates when (the contents of) B is 0, yielding the g.c.d. in A. (Algorithm derived from Scott 2009:13; symbols and drawing style from Tausworthe 1977).
Explanation:
Flowchart of an algorithm (Euclid's algorithm) for calculating the greatest common divisor (g.c.d.) of two numbers a and b in locations named A and B. The algorithm proceeds by successive subtractions in two loops: IF the test B ≥ A yields "yes" or "true" (more accurately, the number b in location B is greater than or equal to the number a in location A) THEN, the algorithm specifies B ← B − A (meaning the number b − a replaces the old b). Similarly, IF A > B, THEN A ← A − B. The process terminates when (the contents of) B is 0, yielding the g.c.d. in A. (Algorithm derived from Scott 2009:13; symbols and drawing style from Tausworthe 1977).
Answer:
Makes it easier to read... summarize cite electronic versions of editions
The Lucent connector(LC) is a type of fiber optic connector used here.
Explanation:
A Lucent connector (LC) is a type of fiber optic connector connects to a terminating device by pushing the connector into the terminating device and can be removed by depressing the tab on the connector and pulling it out of the terminating device.
It is a standard ceramic Ferrule connector and has good performance and is favored for single mode.
LC is a latched connector which have same handling capacities like SC. They have small flange on top similar to an RJ-45 connector that aids secure connection. It has a smaller connector housing and a smaller 1.25 mm ferrule.
Answer: Bottom up approach
Explanation:
We should start from the bottom i.e.starting from the physical layer by inspecting the lan, switches, router and also as we move up the level we also need to check the software application and the various routing protocols at each successive levels.
Hence, we use bottom up approach.
Answer:
11 bit slot will be needed
Explanation:
The number of prime numbers between 1 through 16
= 2, 3 , 5, 7, 11 and 13
hence we can say 6 stations are to use the shared channel
Given that all the stations are ready simultaneously
The number of bit slots that will be needed to handle the contention will be 11 bits :
slot 1 : 2, 3, 5 , 7, 11 , 13
slot 2 : 2,3, 5, 7
slot 3 : 2, 3
slot 4 : 2 . slot 5 : 3 . slot 6 : 5,7. slot 7 : 5 . slot 8 : 7. slot 9: 11,13.
slot 10 : 11. slot 11 : 13
