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Keith_Richards [23]
3 years ago
15

After the data are appropriately processed, transformed, and stored, what is a good starting point for data mining?

Computers and Technology
1 answer:
Oksana_A [137]3 years ago
7 0

Data visualization

Data visualization is a good starting point for data mining. There are several approaches to data mining that supports smart decisions. Data visualization places data in a visual context. It extracts the data in a clear and understandable way without any form of reading or writing. Results are displayed in the form of pie charts, graphs, and any other statistical representation. Such multidimensional views of data aid in developing a preliminary understanding of the trends that are hidden in the data set.

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5 0
2 years ago
Assume the following two classes as Person and Working: class Person { int personID, age; String fName, middleName, lastName; ..
Troyanec [42]

Answer:

A)

This is an example of tight coupling since the class Working has to have an idea of how Person is implemented to complete its own implementation.

B)

Any change in the Person class would require a change in the working class too.

C)

CODE

class Person {

int personID, age;

String fName, middleName, lastName;

public int getAge() {

return age;

}

}

// end of Person class

class Working extends Person {

boolean isUnderEighteen() {

if (super.getAge() <18) {

System.out.println("The person is under age and cannot work");

return true;

}

else {

System.out.println("The person can legitimately work");

return false;

}

}

}

Explanation:

4 0
3 years ago
Which of these situations would benefit from the AutoRecover feature? Check all that apply.
UNO [17]

Answer: Your friend wants you to email her.

Explanation:

3 0
2 years ago
Read 2 more answers
Write two recursive versions of the function minInArray. The function will be given a sequence of elements and should return the
Viktor [21]

Answer:

Following are the code to this question:

#include <iostream>//defining header file

using namespace std;//using namespace

int minInArray1(int arr[],int arrSize)//declaring method minInArray1

{

if(arrSize == 1)//use if block to check arrSize value is equal to 1  

{

return arr[0];//return first element of array

}

else //defining else block

{

int max= minInArray1(arr, arrSize-1);//use integer variable max to call method recursively  

if(arr[arrSize-1] < max)//use if block to check array value  

{

max = arr[arrSize-1];//use max to hold array value

}

return max;//return max variable value

}

}

int minInArray2(int arr[], int low, int high)//defining a method minInArray2  

{

if(low == high) //use if to check low and high variable value are equal

{

return arr[low];//return low variable value

}

else //defining else block

{

int minimum = minInArray2(arr, low+1, high);//defining integer variable minimum to call method minInArray2 recursively

if(arr[low] < minimum)

{

minimum = arr[low];//use minimum variable to hold array value

}

return minimum;//return minimum value

}

}

int main()//defining main method

{

int arr[10] = { 9, -2, 14, 12, 3, 6, 2, 1, -9, 15 };//defining an array arr

int r1, r2, r3, r4;//defining integer variable

r1 = minInArray1(arr, 10);//use r1 variable to call minInArray1 and hold its return value

r2 = minInArray2(arr, 0, 9);//use r1 variable to call minInArray2 and hold its return value

cout << r1 << " " << r2 << endl; //use print method to print r1 and r2 variable value

r3 = minInArray2(arr, 2, 5);//use r3 variable to call minInArray1 and hold its return value

r4 = minInArray1(arr + 2, 4); //use r4 variable to call minInArray2 and hold its return value

cout<<r3<< " " <<r4<<endl; //use print method to print r3 and r4 variable value

return 0;

}

Output:

please find the attached file.

Explanation:

In the given code two methods, "minInArray1 and minInArray2" is defined,  in the "minInArray1" it accepts two-variable "array and arrSize" as the parameter, and in the "minInArray2" method it accepts three integer variable "array, low, and high" as the parameter.

  • In the "minInArray1" method, and if the block it checks array size value equal to 1 if the condition is true it will return the first element of the array, and in the else block the max variable is defined, that calling method recursively
  • and store its value.
  • In the "minInArray2" method, an if the block it checks low and high variable value is equal. if the condition is true it will return a low array value. In the next step, the minimum value is defined, which checks the element of the array and uses a low array to store its value.
  • In the main method an array and four integer variable "r1, r2, r3, and r4" is defined, which calls two methods "minInArray1 and minInArray2" and use print method to print its value.
7 0
3 years ago
A company has a custom object named Warehouse. Each Warehouse record has a distinct record owner, and is related to a parent Acc
PilotLPTM [1.2K]

Answer:

Lookup.

Explanation:

Lookup is the relationship that developer would use to relate the Account to the Warehouse.

8 0
3 years ago
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