D. A spike of electricity. They are fast and have a short duration.
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Pretty sure its called the grooming process
<span>2. basketball
This is a classic case of overloading in C++. You have 2 functions, both named "printSport", but one of the functions receives an input of type double, and the other receives an input of type int. The specified method call passes a parameter of type int, so the version of printSport is called that receives a parameter of type int. And that version of printSport only prints the word "basketball". The other version of printSport is never called at all.</span>
Answer:
See explaination for the code
Explanation:
def wordsOfFrequency(words, freq):
d = {}
res = []
for i in range(len(words)):
if(words[i].lower() in d):
d[words[i].lower()] = d[words[i].lower()] + 1
else:
d[words[i].lower()] = 1
for word in words:
if d[word.lower()]==freq:
res.append(word)
return res
Note:
First a dictionary is created to keep the count of the lowercase form of each word.
Then, using another for loop, each word count is matched with the freq, if it matches, the word is appended to the result list res.
Finally the res list is appended.
