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Marianna [84]
2 years ago
7

20. CHEMISTRY The nucleus of a certain atom is 10-13 centimeters across. If the

Mathematics
1 answer:
lys-0071 [83]2 years ago
8 0

The magnitude of the second atom relative to the first = 10⁻¹¹ / 10⁻¹³ = 100

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more variables or numbers.

The magnitude of the second atom relative to the first = magnitude of second atom / magnitude of first atom

The magnitude of the second atom relative to the first = 10⁻¹¹ / 10⁻¹³ = 100

Find out more on Equation at: brainly.com/question/13763238

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Solution of this equation sqrt x+10-9=-7
myrzilka [38]
Original equation 
<span>√x+10-9 = -7

</span>Isolate
<span>√x+10 = 9-7
</span>
<span>√x+10 = 2
</span> Raise both sides to the second power
<span> (√x+10)2 = (2)2

</span> After squaring 
<span> x+10 = 4
</span>
 x + 6 = 0

so the answer is x=-6
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3 years ago
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Please please please help me ASAP!!
Verdich [7]

Answer:

76

Step-by-step explanation:

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3 years ago
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Help me please this is due today
Grace [21]

\huge\mathtt\blue{answer}

D) 54

Step-by-step explanation:

input f(4) into x

f(x) = x² + 8x + 6

f(4) = (4)² + 8(4) + 6

f(4) = 16 + 32 + 6

f(4) = 54

4 0
3 years ago
Againnnnn pls helpppp
artcher [175]

Answer: B

Step-by-step explanation:

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3 years ago
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Part A:
rewona [7]

Part B - Question 1

Distance for the spacecraft to travel from Venus to Jupiter = Distance of Jupiter from Sun - Distance of Venus from Sun

⇒ Distance for the spacecraft to travel from Venus to Jupiter = 4.838 × 10⁸ - 6.724 × 10⁷

⇒ Distance for the spacecraft to travel from Venus to Jupiter = 483,800,000 - 67,240,000

⇒ Distance for the spacecraft to travel from Venus to Jupiter = 416,560,000

⇒ Distance for the spacecraft to travel from Venus to Jupiter = 4.1656 × 10⁸

Part B - Question 2  

Combined distance of Mercury, Venus, and Earth from the Sun = Distance of Mercury from Sun + Distance of Venus from Sun + Distance of Earth from Sun

⇒ Combined distance of Mercury, Venus, and Earth from the Sun = 5.7909 × 10⁷ + 6.724 × 10⁷ + 9.296 × 10⁷

⇒ Combined distance of Mercury, Venus, and Earth from the Sun = 21.8109 × 10⁷

⇒ Combined distance of Mercury, Venus, and Earth from the Sun = 2.18109 × 10⁸

Distance of Neptune from the Sun = 2.793 × 10⁹

Hence, we can see that the combined distance of Mercury, Venus and Earth from the Sun is <u>less</u> than that of Neptune from the Sun.

Part B - Question 3

If Earth was 10 times farther away from the sun, then the new distance between the Sun and the Earth = 10 × 9.296 × 10⁷

⇒ New distance between the Sun and the Earth = 9.296 × 10⁸

Now, the Earth will be closest to Saturn, which is 8.907 × 10⁸ away from the Sun


New Distance between Earth and Saturn = Distance of Earth from Sun - Distance of Saturn from Sun


⇒ New Distance between Earth and Saturn = 9.296 × 10⁸ - 8.907 × 10⁸

⇒ New Distance between Earth and Saturn = 0.389 × 10⁸

⇒ New Distance between Earth and Saturn = 3.89 × 10⁷ (in scientific notation)

⇒ New Distance between Earth and Saturn = 38,900,000 (in standard notation)

Part B - Question 4

Speed of space shuttle = 28,000 km per hour

Time spent to travel from Saturn to Earth = \frac{\text{Distance between Saturn and Earth}}{\text{Speed of space shuttle} }

⇒Time spent to travel from Saturn to Earth = \frac{\text{Distance of Saturn from Sun - Distance of Earth from Sun}}{\text{Speed of space shuttle} }

⇒Time spent to travel from Saturn to Earth = \frac{8.907 * 10^8 - 9.296 * 10^7}{28,000}

⇒Time spent to travel from Saturn to Earth = \frac{797,740,000 }{28,000}

⇒Time spent to travel from Saturn to Earth = 28,490.7 hours

⇒Time spent to travel from Saturn to Earth = 28,491 hours

Hence, it will take 28,491 hours or 2.8491 x 10⁵ hours for the space shuttle to travel from Saturn to Earth.

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3 years ago
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