23
1 day is equal to 0.14285714 weeks, so multiply that by the number of days.
Answer:
The second option, y + 2x = 10, is the correct answer for this problem.
Step-by-step explanation:
There are many different ways to solve this problem. I am going to pick a point represented in the table and plug its values into the given equations to find the correct response.
From the table, we can conclude that the point (0,10) must satisfy the equation. This means that if we plug in 0 for x and 10 for y into the equations below, we should get a true statement.
y - 2x = 14
10 - 2(0) = 14
10 = 14
Since 10 is not equal to 14, we know that the first option is incorrect.
y + 2x = 10
10 + 2(0) = 10
10 = 10
Therefore, the second option may be our answer, but we should make sure the other options are incorrect.
2y + x = 23
2(10) + 0 = 23
20 = 23
Since 20 is not equal to 23, we know that the third option is incorrect.
y + x = 11
10 + 0 = 11
Since 10 is not equal to 11, we know that the fourth option is also incorrect.
Since the second option is the only answer that yielded a true statement when a point from the table was plugged in, we can conclude that the second option (y + 2x = 10) is the answer. If you wanted to make sure, you could plug in each of the points represented in the table and confirm that they too make the equation true.
Hope this helps!
Answer:
Step-by-step explanation:
Since the incubation times are approximately normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = incubation times of fertilized eggs in days
µ = mean incubation time
σ = standard deviation
From the information given,
µ = 19 days
σ = 1 day
a) For the 20th percentile for incubation times, it means that 20% of the incubation times are below or even equal to 19 days(on the left side). We would determine the z score corresponding to 20%(20/100 = 0.2)
Looking at the normal distribution table, the z score corresponding to the probability value is - 0.84
Therefore,
- 0.84 = (x - 19)/1
x = - 0.84 + 19 = 18.16
b) for the incubation times that make up the middle 97% of fertilized eggs, the probability is 97% that the incubation times lie below and above 19 days. Thus, we would determine 2 z values. From the normal distribution table, the two z values corresponding to 0.97 are
1.89 and - 1.89
For z = 1.89,
1.89 = (x - 19)/1
x = 1.89 + 19 = 20.89 days
For z = - 1.89,
- 1.89 = (x - 19)/1
x = - 1.89 + 19 = 17.11 days
the incubation times that make up the middle 97% of fertilized eggs are
17.11 days and 20.89 days
The whole melon = 5/5
ONE piece went to four children, so
how much of the melon the children got = 1/5
5/5 - 1/5 = 4/5
With 4/5 of the melon, she made 3 fruit cups
4/5 / 3 = 4/5 x 1/3 = 4/15
so she put 4/15 of the melon in the fruit cups
